Good evening
Answer:
<h2>(0 , 5) and (0 , 11)</h2>
Step-by-step explanation:
Suppose M(x , y) is a point of the circle of center (6,3) and radius 10 and M is also a point of the y-axis then the coordonates of M should verify these two equations at the same time:
Then
(0-6)² + (y-3)² = 100
then
36 + (y-3)² = 100
then
(y-3)² = 100 - 36
= 64
then
|y-3| = 8
then
y - 3 = 8 or y - 3 = -8
then
y = 11 or y = 5
then the only points that are on the edge of the circle and on y-axis are:
(0 , 5) and (0 , 11).
:)
Factor <span><span><span>2<span>x^2 </span></span>−<span>2x </span></span>− 12</span><span><span><span>
2<span>x^2 </span></span>− <span>2x </span></span>− 12</span><span>
=<span><span>2<span>(<span>x+2</span>)</span></span><span>(<span>x−3</span>)</span></span></span>
Answer:<span><span>
2<span>(<span>x+2</span>)</span></span><span>(<span>x−3</span><span>)</span></span></span>
I think its a. but i could be wrong
Angle 3 is also 104: and angle 5 and 2 are 76: and angle 6 is 104: 3 and 8 are 104: and 7 and are 76
angle 1 and 6 are verticle angles
angles 7 and 8 are suplimentary
angles 4 and 5 are alternate exterior angles
andgle 2 and 4 are im not sure
Answer:
The Proof for
△ABD ≅ △CBD is below
Step-by-step explanation:
Given:
AD = CD .........BD bisect AC
To Prove:
△ABD ≅ △CBD
Proof:
In ΔABD and ΔCBD
BD ≅ BD ....……….{Reflexive Property}
∠ADB ≅ ∠CDB …………..{Measure of each angle is 90°( )}
AD ≅ CD ....……….{ }
ΔABD ≅ ΔCBD .......….{By Side-Angle-Side Congruence test} ...Proved
