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mihalych1998 [28]
3 years ago
15

Best ever candy will be distributing a new giant size bag of fruit slices. assuming that the ratio relationships remain unchange

d, how many fruit slices will be in the giant size bag?
a.120 fruit slices
b.140 fruit slices
c.160 fruit slices
d.180 fruit slices
Mathematics
2 answers:
zhuklara [117]3 years ago
8 0
B: 140 fruit slices                                                                                                         70 minus 35 equals 35 right? Add 70 to 35, and that's 105 which is in the table. 105+35=140
Hope it helps

KIM [24]3 years ago
3 0

Answer:

140 fruit slices

Orange slices increase by 20 pieces between bag sizes; grape slices increase by 10 pieces; and, cherry slices increase by 5 pieces.

105 + 20 + 10 + 5 = 140 pieces in giant bag

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Step-by-step explanation:

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Answer:

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

z=\frac{0.765 -0.5}{\sqrt{\frac{0.5(1-0.5)}{51}}}=3.785  

p_v =P(z>3.785)=7.68x10^{-5}  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of boys is significantly higher than 0.5.  

Step-by-step explanation:

1) Data given and notation

n=51 represent the random sample taken

X=39 represent the number of boys

\hat p=\frac{39}{51}=0.765 estimated proportion of boys

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that with this method, the probability of a baby being a boy is greater than 0.5.:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.765 -0.5}{\sqrt{\frac{0.5(1-0.5)}{51}}}=3.785  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>3.785)=7.68x10^{-5}  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of boys is significantly higher than 0.5.  

8 0
3 years ago
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Alla [95]
Answer :

Length of rectangle = 14m

Width of rectangle = 12m

Explanation :

p = 2l + 2w = 68

l = w + 2

Substitute:

68 = 2(w + 2) + 2w

68 = 2w + 4 + 2w

4w = 64

w = 16

l = 18


I hope this helped out, have a nice day! :D



(P.s. Both taken from source)

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