Answer:
If you take it in terms of integers,
9+3v may or may not be greater or equal to 6. It depends on the value of the variable you put in.
For eg:- if you substitute the value for v as 2 then 9+3x2=15 which is greater than 6 but if you put in -1 for v then you will get 9+3x(-1)=6
Answer:
- 4x³ - 5x²
Step-by-step explanation:
-x²(-x² + 4x + 5) Distribute
- 4x³ - 5x²
If this answer is correct, please make me Brainliest!
Answer:
V = 43323 mm³
(second answer is already correct)
Step-by-step explanation:
these pennies make up the shape of a cylinder, so, we can solve this question by solving for the volume of a cylinder.
the volume of a cylinder can be found with the formula:
V = πr²h
(V = volume ; π = pi ; r = radius ; h = height)
We know the diameter of this cylinder is 19.05 mm. Diameter is two times the length of the radius, (diameter is all the way across, radius is from center to outer / halfway across) meaning that we can find the radius by dividing 19.05 by 2.
diameter = 19.05
radius = 19.05 / 2 = 9.525
so, r = 9.525
we also are given the height of this cylinder, 38 mm
so, h = 38
π = 3.14159 (π is a constant)
plugging our measurements into the volume formula:
V = πr²h
V = (3.14159)(9.525²)(38)
V = (3.14159)(362.9025)(38)
V = 43323.4894628
[rounded to V = 43323 mm³]
And yes, the volume is not affected by a change in shape. (you are correct)
hope this helps!!
Answer:
(x+2) (x+3) (x-5)
Step-by-step explanation:
x³-19x-30 = (x+2) (x²+ax-15) ... x³=x*(1*x²) while -30= (2)*(-15)
x³ +<u> 0</u>*x² - 19x -30 = x³ + (<u>2+a</u>)x² + (2a-15)x -30
2+a = 0
a = -2
x³-19x-30 = (x+2) (x²-2x-15) = (x+2) (x+3) (x-5)
Answer:
a. f(-1)=12
b. f(2t)=16t²-6t+5
c. f(t-2)=4t²-19t+27
Step-by-step explanation:
For a, b, c, we are given an input. We plug that into f(x) to find our answers.
a. f(-1)=12
f(-1)=4(-1)²-3(-1)+5
f(-1)=4+3+5
f(-1)=12
-------------------------------------------------------------------------------------------------------------
b. f(2t)=16t²-6t+5
f(2t)=4(2t)²-3(2t)+5
f(2t)=4(4t²)-6t+5
f(2t)=16t²-6t+5
-------------------------------------------------------------------------------------------------------------
c. f(t-2)=4t²-19t+27
f(t-2)=4(t-2)²-3(t-2)+5
f(t-2)=4(t²-4t+4)-3t+6+5
f(t-2)=4t²-16t+16-3t+6+5
f(t-2)=4t²-19t+27
