Answer:
1,333 frogs
Step-by-step explanation:
okay so we know that mass remains conserved no matter where you are.
same here ^^
if the total mass of brass is 200 kg
the total mass of the new frogs formed from it when put together will be the same :)
and if there were n such frogs formed
we have,
total mass = n × mass of each frog
200 = n × 3/ 20
n = 4000/ 3
so it becomes something like 1,333.33
that is nearly 1,333 frogs can be made out of 200 kg of brass each weighing 3/ 20kg (the last ones a bit less to make upto 200kg)
When an equation has a line with an undefined slope, it means that the line is vertical.
(2,5); 2 is the x - coordinate and 5 is the y - coordinate
Slope - intercept form: y = mx + b
As shown above, the equation would've been written in slope - intercept form, where 'm' represents the slope and 'b' represents the y - intercept. However, in this case, the slope is undefined.
In the equation, you are ONLY looking for the x - intercept. Therefore, the x - intercept is 5, so that may be the equation of the line.
x = 5
Answer:D
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
Please have a look at the attached photo.
My answer:
A solution is (-1,4) means that point of intercept is (-1,4)
<=> when x=-1 so y = 4 for both equations
From the 4 possible answers, only graph D meets the requirement.
Hope it will find you well
Answer:
3 3/4
Step-by-step explanation:
5 times 3/4 equals 3 3/4! :)
Answer:
<em>The 95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>
(48.937 , 50.863)
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given data random sample of 46 bins, the sample mean amount was 49.9 pounds and the sample standard deviation was 3.641
<em>The sample size 'n' =46</em>
<em>mean of the sample x⁻ = 49.9</em>
<em>Standard deviation of the sample S = 3.641</em>
<u>Confidence intervals:</u><em>-</em>
<em>The 95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>
<em></em>
<em></em>
<em>Degrees of freedom = n-1 = 46-1 =45</em>
<em>The tabulated value t₀.₉₆ = 1.794 ( from t-table)</em>
<em></em>
<em></em>
(49.9 -0.9630 , 49.9+0.9630)
(48.937 , 50.863)
<u>Conclusion:</u>-
<em>The 95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>
(48.937 , 50.863)