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3 years ago

___ .128 <<<< is it rational or irrational?

1 answer:

6 0

This would be rational. If it were an irrational number, the integers on the right side of the decimal would go on forever.

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Can someone please help me with 4 and 5 ???

Montano1993 [528]

Answer:

4. D

A: -25.5=a

B: b=-4

C: c=12

D: d=8

Step-by-step explanation:

4.Between a and d they are the 2 bigger values but D was the greatest out of all of them. - divided by a - will result as a positive and 7/9=0.77 and 19/12 *I looked for the least common factor and multiplied numerator and denominator to 12 depending on the denominators value. Ex: since one of my denominators was 4, I multiply the whole fraction by 3 to get 9/12 and the other was 5/6 times 2 is 10/12 and just add 10/12 by 9/12 which is 19/12.

A: All I did was multiply 8.5 and -3 and get -25.5=a.

B: I add 7 on both sides of the equation and -7 and 7 get canceled off and -11+7=-4. b=4.

C: I multiplied - to -3 and got 3, now I can subtract -3 on both sides. 15-3=12 so c=12.

D. I had to divide by 4 on both sides to get d by itself. 32/4=8 so final answer would be d=8.

5 0

3 years ago

Brianna is going to a carnival that has games and rides. Each game costs $1.25 and each ride costs $3.75. Brianna spent $18.75 a

maxonik [38]

Answer:

6 games and 3 rides

Step-by-step explanation:

Let the number of games Brianna played be x,

and the number of rides she went on be y.

Total cost for games= 1.25x

Total cost for rides= 3.75y

Since number of games is twice the number of rides,

x= 2y -----(1)

Total costs= cost of games +cost of rides

$18.75= 1.25x +3.75y$

Multiply the whole equation by 4 to remove the decimals:

$75= 5x +15y$

Simplify by dividing the whole equation by 5:

$15 = x + 3y$

Label the equation:

x +3y= 15 -----(2)

Although we can solve these 2 equations by substitution, since the question requires us to graphically solve, we have to graph 2 linear lines.

I will choose 3 points to plot on the graph for each equation:

x= 2y -----(1)

$\begin{tabular}{|c|c|c|c|} \cline{1-4}x & 2(1) = 2&2(2) = 4&2(3) = 6\\ \cline{1-4}y & 1 &2&3\\ \cline{1-4}\end{tabular}$

x +3y= 15 -----(2)

x= -3y +15

$\begin{tabular}{|c|c|c|c|} \cline{1-4}x & -3(1)+15= 12& -3(2)+15= 9& -3(3)+15= 6\\ \cline{1-4}y & 1 &2&3\\ \cline{1-4}\end{tabular}$

Let's plot these points on a graph paper. Then, join them with a straight line for each straight line graph. Please see the attached picture for the graph.

From (1): y= ½x

From (2): 3y= 15 -x

y= 5 -⅓x

From the graph, the solution of the equation is (6,3). The solution is the point on the graph in which the 2 lines intersect.

x- coordinate: 6

y- coordinate: 3

Thus, Brianna played 6 games and went on 3 rides.