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Margarita [4]
3 years ago
5

So, the area Find the area of the figure of

Mathematics
2 answers:
ch4aika [34]3 years ago
7 0

Answer:

The area of the figure is 117m²

Step-by-step explanation:

In this problem, you have two shapes. One shape is a rectangle. The other shape is a triangle.

Area of a rectangle = b*h = 9*7 = 63

Area of a triangle = \frac{1}{2}(b*h) =

Since there are two triangles, you will multiply the area of the one triangle in the figure by 2.

27*2 = 54

Now, you add up the areas!

54 + 63 = 117

So, the area of the figure is 117m²

labwork [276]3 years ago
7 0

Answer:

So for this just times width times height

Step-by-step explanation:

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What is 2.99 x 0.6 in dollars and cents plz help:(
Natasha2012 [34]

Answer:

the answer is 1. 794

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Two chicken coops are to be built adjacent to one another from 168 ft of fencing. What dimensions should be used to maximize the
Cerrena [4.2K]

Answer:

21 ft by 28 ft

Step-by-step explanation:

To maximize the area, see the attached.

Perimeter will be 4l+3w which is equal to the fencing perimeter, given as 168

4l+3w=168

Making l the subject then

4l=168-3w

l=42-¾w

Area of individual land will be lw and substituting l with l=42-¾w

Then

A=lw=(42-¾w)w=42w-¾w²

A=42w-¾w²

Getting the first derivative of the above with respect to w rhen

42-w6/4=0

w6/4=42

w=42*4/6=28

Since

l=42-¾w=42-¾(28)=21

Therefore, maximum dimensions are 21 for l and 28 for w

4 0
2 years ago
Need help with 2 and 3 ASAP PLEASE SHOW WORK it’s due soon please
Deffense [45]

Answer:

The volume of the cone is 25.13, the other one is 167.55

Step-by-step explanation:

v = 1/3pi(2)^2(6)

simplify and divide the above.

v = 25.13

1/3pi(4)^2(10)

= 167.55

4 0
3 years ago
You roll a pair of fair dice until you roll “doubles” (i.e., both dice are the same). what is the expected number, e[n], of roll
bonufazy [111]

We need to define our outcomes and events.

 

Finding the probability<span> of each event occurring separately, and then multiplying the probabilities is the step to <span>finding  the probability</span> of two independent events that occur in sequence.

</span>

<span>
To solve this problem, we take note of this:</span>

 

The roll of the two dice are denoted by the pair

(I, j) ∈ S={ (1, 1),(1, 2),..., (6,6) }

Each pair is an outcome. There are 36 pairs and each has probability 1/36. The event “doubles” is { (1, 1),(2, 2)(6, 6) } has probability p= 6/36 = 1/6. If we define ”doubles” as a successful roll, the number of rolls N until we observe doubles is a geometric (p) random variable and has expected value E[N] = 1/p = 6.

3 0
3 years ago
Jack has some marbles. He has ten more red marbles than blue marbles. He has fewer yellow marbles than blue marbles.
kap26 [50]

Answer:

<u>Jack has at least 15 marbles: 12 red, 2 blue and 1 yellow.</u>

Step-by-step explanation:

1. Let's review the information given to us to solve the problem correctly:

Number of red marbles = 10 more than blue marbles

Number of yellow marbles fewer than blue marbles

2. How many of each color marble could Jack have?

r = Number of red marbles

b = Number of blue marbles

y = Number of yellow marbles

r = b + 10

y < b

If y = 1, then b ≥ 2, and r = b + 10,

fulfilling the three conditions, we have:

<u>y = 1, b = 2, and r = 12</u>

5 0
3 years ago
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