The rectangle with maximum area will actually be a square.
Each side will be of length 7/4 = 1 3/4.
20+j*2
Ye, that's about right aye

you divide both the top and bottom number by the highest number that can go into both without giving you a decimal . the highest number that can go into both parts of the fraction is 7 . 56/7= 8 and 63/7 = 9 therefore the answer is
Answer:
1. two square root of ten
Step-by-step explanation:
Given expression is:
![\[\sqrt{5}* \sqrt{8}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B5%7D%2A%20%5Csqrt%7B8%7D%5C%5D)
Simplifying the expression:
![\[\sqrt{5}* \sqrt{4 \ast 2}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B5%7D%2A%20%5Csqrt%7B4%20%5Cast%202%7D%5C%5D)
= ![\[\sqrt{5}* \sqrt{4}*\sqrt{2}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B5%7D%2A%20%5Csqrt%7B4%7D%2A%5Csqrt%7B2%7D%5C%5D)
= ![\[\sqrt{5}* 2*\sqrt{2}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B5%7D%2A%202%2A%5Csqrt%7B2%7D%5C%5D)
= ![\[2 * \sqrt{5} * \sqrt{2}\]](https://tex.z-dn.net/?f=%5C%5B2%20%2A%20%5Csqrt%7B5%7D%20%2A%20%5Csqrt%7B2%7D%5C%5D)
= ![\[2 * \sqrt{10}\]](https://tex.z-dn.net/?f=%5C%5B2%20%2A%20%5Csqrt%7B10%7D%5C%5D)
So among the given options, option 1 is the correct one,namely, two square root of ten.