Answer:
76.16 kilograms of food
Step-by-step explanation:
Number of cyclist = 32
Food per cyclist = 8.33 kilograms
Days of the trip = 7 days
Food per cyclist per day = 8.33 kg / 7
= 1.19kg food per day for each cyclist
how many kilograms of food will the group be carrying at the end of Day 5?
5 days out of 7 days = 2 days
Each cyclist will have to carry = 2 × 1.19 kg of food for the remaining two days
= 2 × 1.19
= 2.38 kilograms of food for two days
32 cyclist for 2 days = 32 × 2.38 kg of food
= 76.16 kilograms of food
The group will be carrying 76.16 kilograms of food at the end of Day 5
Answer: a. n= 1068
b. n= 164
Step-by-step explanation:
The formula to find the sample size :

, where p=prior population proportion , z* = critical z-value and E = Margin of error.
Here , let p=proportion of computers that use a new operating system.
Given : Confidence level = 95%
i.e. z* = 1.96 [by z-table]
Margin of error : E = 3% =0.03
a. If p is unknown , then we assume p=0.5
Then, 
i.e. n= 1068
b. p=0.96
Then, 
i.e. n= 164.
The answer to the problem is approximately 19 liters
The addition property of equality
Answer:
yes
Step-by-step explanation: