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xenn [34]
3 years ago
8

Which of the following ordered pairs in a solution of the equation y equals negative 4 x squared​

Mathematics
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

Step-by-step explanation:

The equation is y = -4x²

Next time, please share the answer choices.

Here's a short table of possible solutions:

x     -x²    (x, y)

-----  ------  ---------

 0       0    (0, 0)

2      -4     (2, -4)

-3     -9      (-3, -9)

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In a triangle the measure of the first angle is 24 degrees more than the second angle. the measure of the third angle is four ti
Leona [35]

The greatest angle in the given triangle is 104 degrees.

<h3>What is a triangle?</h3>
  • The polygon with 3 sides, three vertices, and three angles is known as a triangle.
  • A triangle's overall number of degrees is always 180 degrees.

Given:

  • Let, the second angle has a measurement of x degrees.
  • The first angle's measurement is 24 degrees greater than the second angle's measurement.
  • As a result, the first angle is (24+x) degrees.
  • The third angle is four times as large as the second.
  • As a result, the third angle has a measure of 4x.

So,

  • (24 + x) + x + 4x = 180
  • 6x = 124 - 48
  • 6x = 156
  • x = 156/6
  • x = 26

As a result, the second angle has a measurement of 26 degrees.

The first angle's measurement is now 24 degrees greater than the second angle's measurement.

Now,

  • = 24 + 26
  • = 50

As a result, the first angle has a measure of 50 degrees.

The third angle is now four times the size of the second angle.

So,

  • 4 × 26 = 104

Therefore, the greatest angle in the given triangle is 104 degrees.

Know more about triangles here:

brainly.com/question/17335144

#SPJ4

7 0
2 years ago
The first side of a triangle is 3 inches shorter than the second side, and 2 inches longer than the third side. How long is each
ziro4ka [17]

Answer:

the length of the first side of the triangle is \frac{28}{3}\ in

the length of the second side of the triangle is \frac{37}{3}\ in

the length of the third side of the triangle is \frac{19}{3}\ in

Step-by-step explanation:

Let

x-----> the length of the first side of a triangle

y----> the length of the second side of a triangle

z---> the length of the third side of a triangle

we know that

x=y-3

y=x+3 -----> equation A

x=z+3

z=x-3  -----> equation B

The perimeter of the triangle is equal to

P=x+y+z

P=28\ in

so

28=x+y+z -----> equation C

substitute equation A and equation B in equation C

28=x+(x+3)+(x-3)

solve for x

28=3x

x=\frac{28}{3}\ in

Find the value of each side

the first side of a triangle is x

x=\frac{28}{3}\ in

the second side of a triangle is y

y=\frac{28}{3}+3=\frac{37}{3}\ in

the third side of a triangle is z

z=\frac{28}{3}-3=\frac{19}{3}\ in

7 0
3 years ago
2^2/5+ 3^1/10 <br> HELP ASAP
gizmo_the_mogwai [7]

Answer:

\sqrt[5]{4}  + \sqrt[10]{3}

Step-by-step explanation:

We sure can write 2^2/5+ 3^1/10 as 2^{\frac{2}{5} } + 3^{\frac{1}{10} }

// use the a^{\frac{m}{n} }  =\sqrt[n]{a^{m} } to transform the expression

Convert 2^{\frac{2}{5} } to \sqrt[5]{2^{2} } = \sqrt[5]{4}                        (here a = 2, n = 5, m = 2)

Then convert  3^{\frac{1}{10} } to \sqrt[10]{3^{1} } = \sqrt[10]{3}             (here a = 3, n = 10, m = 1)

Now we get  2^{\frac{2}{5} } + 3^{\frac{1}{10} } = \sqrt[5]{4}  + \sqrt[10]{3} . This is the simplified form, which is the answer.

6 0
3 years ago
It is desired to draw blood 3 cm up a capillary tube. Assuming a contact angle of 0 degrees and a blood density of 1060 kg/m3, w
JulijaS [17]

Answer:

If we assume a temperature of 20ºc and the blood interfacial surface tension is similar to water interfacial surface tension, the diameter of the capillary tube should be 0.933mm.

Step-by-step explanation:

The Jurin law describes the height a fluid can reach in a capillary tube. This law can be written as:

H=\displaystyle\frac{2\gamma cos(\theta)}{\rho gr}

where γ is the interfacial surface tension, θ is the contact angle with the fluid, ρ is the fluid density, g is the gravity acceleration and r is the tube radius.

If we assume that the interfacial surface tension of blood and water are almost the same, γ=0,0728 N/m at 20ºc. Therefore the diameter of the tube will be:

D=2r=\displaystyle\frac{4\gamma cos(\theta)}{\rho gH}=0.933\cdot 10^{-3}m

4 0
3 years ago
What type of credit card is offered to qualified customers for primary sales of a company’s good?
Mashutka [201]
B. Full purpose credit card?

I feel like that makes sense.
6 0
3 years ago
Read 2 more answers
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