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xenn [34]
3 years ago
8

Which of the following ordered pairs in a solution of the equation y equals negative 4 x squared​

Mathematics
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

Step-by-step explanation:

The equation is y = -4x²

Next time, please share the answer choices.

Here's a short table of possible solutions:

x     -x²    (x, y)

-----  ------  ---------

 0       0    (0, 0)

2      -4     (2, -4)

-3     -9      (-3, -9)

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Consider a series system composed of 4 separate components where each component has a 30% chance of failing. Assume each compone
Marina86 [1]

Answer:

16.15% probability that exactly 3 of them would function

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of each system working:

4 components, which means that n = 4

Each has a 30% probability of failing, so p = 1 - 0.3 = 0.7

For the system to work, all 4 components have to work. This is P(X = 4).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.7)^{4}.(0.3)^{0} = 0.2401

0.2401 probability of a system working.

If you have 7 of these systems, what is the probability that exactly 3 of them would function?

Now 7 systems, so n = 7

0.2401 probability of a system working.

We have to find P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{7,3}.(0.2401)^{3}.(0.7599)^{4} = 0.1615

16.15% probability that exactly 3 of them would function

5 0
3 years ago
A function has a domain of {1, 3, 5, 7} and a range of {2, 4, 6}. Which set of ordered pairs represents this function?
Arlecino [84]
For this case we have the following domain:
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 Answer:
 
A. {(1, 2), (3, 4), (5, 6), (7, 2)}
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