Answer:
Solution given:
cscθ -cscθcos²θ
taking common
cscθ(1-cos²θ)
we have
1-cos²θ=sin²θ and cscθ=1/sinθ
now
1/sinθ*sin²θ
=sinθ
so
D)
<u>sin θ</u><u> </u><u>i</u><u>s</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
it's the only one that hasn't been with a positive 2
Answer:
It's B :)
Step-by-step explanation:
Answer:
Feel free to copy and paste:
Use the slope-intercept form to find the slope and y-intercept. To do this, use y=mx+b. Plug the variables where m=1 and b=2. Slope of the line is m and y-intercept is value of b, so the slope is 1 while the y-intercept is (0,2). Any line can be graphed using two points, and using two x values to plug them into the equation to find the corresponding y values: 0=x+2 is (-2,0). Y-intercept is already known, so use the known values and make a table where x= -2,0 and y = 0,2. Now, graph the line using the slope, y-intercept, and known points (-2,0), (0,-2) to plot the graph. Coincidingly, the answer to solve your system of equations will be the x-intercept: (-2,0).
Answer:
The answer is irrational
Step-by-step explanation:
