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2 years ago

What's 18➗4.52? Plz help

2 answers:

6 0

If you want to calculate 18/4.52, you can do this using the following steps:

18/4.52 = 18 / 4 52/100 = 18 / 452/100 = 18 * 100/452 = 1800/452 = 450/113 = 3.98

The correct result is 3.98.

Westkost [7]2 years ago

6 0

3.982 is the answer to 18 divided by 4.52

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PLEASE ANYONE HELP I NEED IT DONE BY 11:59 this is the second part to the first part six question all together someone please he

Archy [21]

I believe question 4 is 40 but I’m not sure

6 0

2 years ago

Lagrange multipliers have a definite meaning in load balancing for electric network problems. Consider the generators that can o

Ivahew [28]

Answer:

The load balance $(x_1,x_2,x_3)=(545.5,272.7,181.8)$ Mw minimizes the total cost

Step-by-step explanation:

<u>Optimizing With Lagrange Multipliers</u>

When a multivariable function f is to be maximized or minimized, the Lagrange multipliers method is a pretty common and easy tool to apply when the restrictions are in the form of equalities.

Consider three generators that can output xi megawatts, with i ranging from 1 to 3. The set of unknown variables is x1, x2, x3.

The cost of each generator is given by the formula

$\displaystyle C_i=3x_i+\frac{i}{40}x_i^2$

It means the cost for each generator is expanded as

$\displaystyle C_1=3x_1+\frac{1}{40}x_1^2$

$\displaystyle C_2=3x_2+\frac{2}{40}x_2^2$

$\displaystyle C_3=3x_3+\frac{3}{40}x_3^2$

The total cost of production is

$\displaystyle C(x_1,x_2,x_3)=3x_1+\frac{1}{40}x_1^2+3x_2+\frac{2}{40}x_2^2+3x_3+\frac{3}{40}x_3^2$

Simplifying and rearranging, we have the objective function to minimize:

$\displaystyle C(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)$

The restriction can be modeled as a function g(x)=0:

$g: x_1+x_2+x_3=1000$

$g(x_1,x_2,x_3)= x_1+x_2+x_3-1000$

We now construct the auxiliary function

$f(x_1,x_2,x_3)=C(x_1,x_2,x_3)-\lambda g(x_1,x_2,x_3)$

$\displaystyle f(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)-\lambda (x_1+x_2+x_3-1000)$

We find all the partial derivatives of f and equate them to 0

$\displaystyle f_{x1}=3+\frac{2}{40}x_1-\lambda=0$

$\displaystyle f_{x2}=3+\frac{4}{40}x_2-\lambda=0$

$\displaystyle f_{x3}=3+\frac{6}{40}x_3-\lambda=0$

$f_\lambda=x_1+x_2+x_3-1000=0$

Solving for \lambda in the three first equations, we have

$\displaystyle \lambda=3+\frac{2}{40}x_1$

$\displaystyle \lambda=3+\frac{4}{40}x_2$

$\displaystyle \lambda=3+\frac{6}{40}x_3$

Equating them, we find:

$x_1=3x_3$

$\displaystyle x_2=\frac{3}{2}x_3$

Replacing into the restriction (or the fourth derivative)

$x_1+x_2+x_3-1000=0$

$\displaystyle 3x_3+\frac{3}{2}x_3+x_3-1000=0$

$\displaystyle \frac{11}{2}x_3=1000$

$x_3=181.8\ MW$

And also

$x_1=545.5\ MW$

$x_2=272.7\ MW$

The load balance $(x_1,x_2,x_3)=(545.5,272.7,181.8)$ Mw minimizes the total cost

5 0

3 years ago

Which of the following must be true?

Ilya [14]

The answer is C, when numbers or variables are between "|" (also called bars) it means to remove any negative symbols and think of it as a positive number. If the number is already positive you keep it a positive number.

5 0

3 years ago

Geometry. Attached photo. PLEASE FOR THE LOVE OF GOD.

kupik [55]

Answer:

m<C = 42°

Step-by-step explanation:

Given:

m<A = (2x - 2)°

m<C = (4x - 6)°

m<DBC = (5x + 4)°

Thus:

m<DBC = m<A + m<C (exterior angle theorem of a triangle)

(5x + 4)° = (2x - 2)° + (4x - 6)°

Solve for x

5x + 4 = 2x - 2 + 4x - 6

Collect like terms

5x + 4 = 6x - 8

5x - 6x = -4 - 8

-x = -12

Divide both sides by -1

x = 12

✔️m<C = (4x - 6)°

Plug in the value of x

m<C = 4(12) - 6 = 48 - 6

m<C = 42°

4 0

2 years ago

Read 2 more answers

Find the errors and correct the following mathematical sentences.

matrenka [14]

Answer:

This is your answer

4 0

3 years ago