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lina2011 [118]
3 years ago
8

Which number is the least? 2.07, 2.94, 2.81, 2.069

Mathematics
2 answers:
stiks02 [169]3 years ago
8 0
Number 2.069 is the least

Anton [14]3 years ago
4 0
2.069 should be the least
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HELP PLEASE
Fiesta28 [93]
The correct point of the graph would be B. (2,-5)
8 0
3 years ago
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Write an expression that is equivalont to 4(5+2)-3h,​
zhuklara [117]

Answer:

28 - 3h

Step-by-step explanation:

We must do the work seen inside parentheses first.

Thus, we havve 4(7) - 3h, which simplifies to

28 - 3h

8 0
3 years ago
PLZ HELP<br> divide<br> 4 1/5 ÷ 2/3 <br> express your answer as a mixed number in simplest from
Sunny_sXe [5.5K]

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63/15

Step-by-step explanation:

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8 0
3 years ago
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How many ways can you arrange the letters in the word prime?
Jobisdone [24]
There are 5 letters in the word "prime"

Imagine we had 5 slots to fill. They are empty initially. 
Slot 1 has 5 choices to pick from
Once we pick a letter, we have 4 choices left over for slot 2
Slot 3 will have 3 choices
Slot 4 will have 2 choices
Slot 5 will have 1 choice

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which multiplies out to 5*4*3*2*1 = 120

There are 120 unique ways to arrange the letters. Order matters. Because order matters, this is a permutation.
7 0
3 years ago
The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.1. This distribution
cluponka [151]

Answer:

Step-by-step explanation:

Hello!

The definition of the Central Limi Theorem states that:

Be a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

X[bar]≈N(μ;σ²/n)

If the variable of interest is X: the number of accidents per week at a hazardous intersection.

There is no information about the distribution of this variable, but a sample of n= 52 weeks was taken, and since the sample is large enough you can approximate the distribution of the sample mean to normal. With population mean μ= 2.2 and standard deviation σ/√n= 1.1/√52= 0.15

I hope it helps!

5 0
3 years ago
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