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wlad13 [49]
3 years ago
5

Evaluate the integral f*dr where f(x,y)=<-y,x^2> and c consists of te arc of the parabola y=2x^2 from (-1,2) to (1,2)

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0
y=2x^2\implies\mathbf r(x)=\langle x,2x^2\rangle

\displaystyle\int_C\mathbf F\cdot\mathrm d\mathbf r=\int_{t=-1}^{t=1}\langle-2x^2,x^2\rangle\cdot\langle1,4x\rangle\,\mathrm dx
=\displaystyle\int_{-1}^1(8x^3-2x^2)\,\mathrm dx
=-\dfrac43
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8 0
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Answer:

Step-by-step explanation:

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97.35

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That's how the function would look after you plugged the numbers from the problem in.

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6 0
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What is x?<br><br> 3-2x=21<br><br> Show the steps?
JulsSmile [24]

Answer:

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3 0
3 years ago
Graph the line y=−3x+b if it is known that the graph goes through point: B(5,2)
Nuetrik [128]

Try this solution:

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Using the coordinates of point B (5;2), if to substitute them into the given equation: 2=-3*5+b, ⇒ b=17. It means, that the equation of the line required in the condition is y= -3x+17.

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5 0
3 years ago
Solve for w k=2b-5w/3k
nlexa [21]
k = \frac{2b - 5w}{3k}
3k^{2} = 2b - 5w
3k^{2} + 5w = 2b
5w = 2b - 3k^{2}
w = \frac{2}{5}b - \frac{3}{5}k^{2}
7 0
3 years ago
Read 2 more answers
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