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ycow [4]
4 years ago
9

There are 24 students in mr bobs math class 5/8 of these students earned an a on the geometry assessment how many students earne

d an a
Mathematics
1 answer:
dlinn [17]4 years ago
8 0
Of means multiply

24*5/8=15

15 students earned an A
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Find the distance between the following points using the Pythagorean theorem: (-5, 4) and (8, -3)
3241004551 [841]

First, draw a diagram to visualize the situation:

As we can see, the difference between the x-coordinates of the points is the length of one leg of a right triangle, and the difference between the y-coordinates is the length of the other leg.

Then, for the given points (-5,4) and (8,-3), the distance given by the Pythagorean Theorem is:

\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\  \\ =\sqrt{(8--5)^2+(-3-4)^2} \\  \\ =\sqrt{(13)^2+(-7)^2} \\  \\ =\sqrt{169+49} \\  \\ =\sqrt{218} \\  \\ \approx14.7648... \end{gathered}

Therefore, the distance between the points (-5,4) and (8,-3) is: √218.

5 0
1 year ago
How many gallons and quarts are in 10 quarts
Ipatiy [6.2K]
10 quarts = 2.5 gallons.

There are 4 quarts for every 1 gallon, but because you're finding gallons and not quarts, you do 10 ÷ 4 = 2.5.
7 0
4 years ago
Read 2 more answers
What is the simplified form of the following expression 7(^3√2x)-3(^3√16x)-3(^3√8x)
svlad2 [7]

Answer:

The simplified form of the expression is \sqrt[3]{2x}-6\sqrt[3]{x}

Step-by-step explanation:

Given : Expression 7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}

To Simplified : The expression

Solution :  

Step 1 - Write the expression

7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}

Step 2- Simplify the roots and re-write as

16=2^3\times2 and 8=2^3

7\sqrt[3]{2x}-3\times2\sqrt[3]{2x}-3\times2\sqrt[3]{x}

Step 3- Solve the multiplication

7\sqrt[3]{2x}-6\sqrt[3]{2x}-6\sqrt[3]{x}

Step 4- Taking \sqrt[3]{2x} common from first two terms

\sqrt[3]{2x}(7-6)-6\sqrt[3]{x}

\sqrt[3]{2x}-6\sqrt[3]{x}

Therefore, The simplified form of the expression is \sqrt[3]{2x}-6\sqrt[3]{x}

5 0
3 years ago
Read 2 more answers
14 over 21 simplified
anastassius [24]
2 over 3 is 14 over 21 simplified, dividing both numbers by 7.
4 0
3 years ago
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The cost in dollars of producing x units of a particular telephone is C(x) = x2 – 2500. Find the average rate of change of C wit
erica [24]
The average rate of change over a given interval is the slope of the secant line through the endpoints of the interval.

m = \dfrac{f(b)-f(a)}{b-a} =  \dfrac{f(103)-f(100)}{103-100}\\\\ = \dfrac{(103)^2-2500-[(100)^2-2500]}{103-100} =  \dfrac{609}{3}=203

$203/unit.

The instantaneous rate of change at a certain point is the slope of the tangent line.

We differentiate C to get 2x. We substitute 100 for x to get that the instantaneous rate of change at 100 is $200/unit.

3 0
3 years ago
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