Answer:
The answer is d = C/pi.
Step-by-step explanation:
To solve this equation for the variable d, we must isolate it on the right side of the equation. It is currently being multiplied by pi, so to reverse this action, we should divide both sides of the equation by pi.
c = (pi) * d
c/pi = pi/pi * d
c/pi = d
d = c/pi
Therefore, the answer is d = C/pi.
Hope this helps!
Answer:
The equation, y=3 x,
Step-by-step explanation:
y=Distance traveled
x =Total time
Also, in terms of straight line
Slope =3= uniform Velocity
Point (3,9) and (5,15) represents Distance traveled in 3 (unit of time) =9 unit, and 15 unit=Distance traveled in 5 (Unit of time).
→Alonso is moving with uniform speed=3 (unit of time), as velocity remains constant in the entire process.
To find y you need to insert x into the equation. The equation is y=2x+2, so insert the x on the table to find the y.
y=2(-4)+2=-6
y=2(-2)+2=-2
y=2(0)+2=2
y=2(1)+2=4
y=2(3)+2=8
These follow the equation's rule so it is correct.
Two plot the values of x and y you need to put it in (x,y) then plot it. Then you can check it by using the equation, y=mx+b, the b is the y intercept, so check to see if it starts there, and then check and see if it followings the slope
(-4, -6), (-2, -2), (0, 2), (1, 4), (3, 8)
Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)
- Cutiepatutie ☺❀❤
Answer:
Smith
Step-by-step explanation:
Woodson has fewer than Smith
Smith>Woodson
Woodson has more than Rodriquez
Smith>Woodson>Rodriguez
Blackburn has fewer then Rodriguez
Smith>Woodson>Rodriguez>Blackburn
Answer: On the 29th day
Step-by-step explanation:
According to this problem, no lilypad dies and the lilypads always reproduce, so we can apply the following reasoning.
On the first day there is only 1 lilypad in the pond. On the second day, the lilypad from the first reproduces, so there are 2 lilypads. On day 3, the 2 lilypads from the second day reproduce, so there are 2×2=4 lilypads. Similarly, on day 4 there are 8 lilypads. Following this pattern, on day 30 there are 2×N lilypads, where N is the number of lilypads on day 29.
The pond is full on the 30th day, when there are 2×N lilypads, so it is half-full when it has N lilypads, that is, on the 29th day. Actually, there are
lilypads on the 30th, and
lilypads on the 29th. This can be deduced multiplying succesively by 2.