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Karo-lina-s [1.5K]
3 years ago
13

Find the perimeter of the following shape, rounded to the nearest tenth:

Mathematics
2 answers:
givi [52]3 years ago
4 0

Answer: 17.9


Step-by-step explanation:

A (-3,5)

B (1,7)

C (3,3)

D (-1,1)

To find the perimeter, the distance between each point or the length of each side must be found, so we use the distance formula.

d(distance) = √(x₂-x₁)² + (y₂-y₁)²

So, substitute numbers into the formula...

d = √(1 - -3)² + (7 - 5)² = √4² + 2² = √16 + 4 = √20 = 4.4721359 = Line AB

Repeat the steps and you find tha each length equals the same and that it is a square, so multiply √20 by 4 and you get 17.888543


Or about 17.9

34kurt3 years ago
3 0
Through my research I found a question similar to this and found the right description matching answers: so we have to find the perimeter of this: ''Shape ABCD is shown. Point A is at negative 3, 5. Point B is at 1, 7. Point C is at 3, 3. Point D is at negative 1, 1.''

Answer would be C) 17.9
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polet [3.4K]
Let's focus on the given equation. The C represents the cost, while the x must be the number of tacos, which is what we're solving for. Since we're given the boundary that C must be 300, then the solution would be:

300 = x² - 40x + 610
x² - 40x + 310 = 0

Apply the quadratic formula where a = 1, b = -40 and c = 310. The roots of x are:
x = 29.49≈30
x = 10.51≈11

<em>Thus, she needs to sell either 30 or 11 tacos.</em>

4 0
4 years ago
The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to
Firdavs [7]

Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:

<em>y</em> = -1 - <em>x</em>  ==>  <em>x</em> = -1 - <em>y</em>

<em>y</em> = <em>x</em> - 1  ==>  <em>x</em> = 1 + <em>y</em>

So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.

This means the area is given by the integral,

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The integral with respect to <em>x</em> is trivial:

\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy

For the remaining integral, integrate term-by-term to get

\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.

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3 years ago
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Answer:

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