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Karo-lina-s [1.5K]
3 years ago
13

Find the perimeter of the following shape, rounded to the nearest tenth:

Mathematics
2 answers:
givi [52]3 years ago
4 0

Answer: 17.9


Step-by-step explanation:

A (-3,5)

B (1,7)

C (3,3)

D (-1,1)

To find the perimeter, the distance between each point or the length of each side must be found, so we use the distance formula.

d(distance) = √(x₂-x₁)² + (y₂-y₁)²

So, substitute numbers into the formula...

d = √(1 - -3)² + (7 - 5)² = √4² + 2² = √16 + 4 = √20 = 4.4721359 = Line AB

Repeat the steps and you find tha each length equals the same and that it is a square, so multiply √20 by 4 and you get 17.888543


Or about 17.9

34kurt3 years ago
3 0
Through my research I found a question similar to this and found the right description matching answers: so we have to find the perimeter of this: ''Shape ABCD is shown. Point A is at negative 3, 5. Point B is at 1, 7. Point C is at 3, 3. Point D is at negative 1, 1.''

Answer would be C) 17.9
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Sunny_sXe [5.5K]

Answer:

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Part 2) The vertex is the point (1,8)

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Part 4) The vertex is a minimum

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Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

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if a < 0 then the parabola open downward (vertex is a maximum)

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

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(h,k)=(1,8)

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y=2x^{2}-4x+2+8

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see the attached figure to better understand the problem

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