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3 years ago

2+4q=20 please help me with this problem thank you..

Mathematics

2 answers:

Mashutka [201]3 years ago

8 0

2+4q=20
4q=18
q=9/2

hope this helps u

zysi [14]3 years ago

5 0

First you subtract 2 from both sides which gives you 4q=18 then you want to divide both sides by 4 which means both 4s cancel each other and 18/4=4.5 and you still have the q which means q=4.5 hope this helps

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Is this a quadratic function 2x+13=13

lys-0071 [83]

Answer:

Step-by-step explanation:

Simplifying

2x + 13 = 0

Reorder the terms:

13 + 2x = 0

Solving

13 + 2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-13' to each side of the equation.

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2 years ago

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3 years ago

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allsm [11]

Answer:

Solutions: $x = \frac{-3}{ 4} + i \sqrt{39}$ , $x = \frac{-3}{4} - i \sqrt{39}$

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

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$x = \frac{-3 +/- \sqrt{-39} }{4}$

$x = \frac{-3 + i \sqrt{39} }{4}$ , $x = \frac{-3 - i \sqrt{39} }{4}$

Therefore, the solutions to the given quadratic equation are:

$x = -\frac{3}{ 4} + i \sqrt{39}$ , $x = -\frac{3}{4} - i \sqrt{39}$

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2 years ago

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AveGali [126]

M can be any positive real number.

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