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pychu [463]
3 years ago
11

What is the solution for 8y=-40 ( , )

Mathematics
2 answers:
icang [17]3 years ago
8 0

8y = -40

/8      /8  divide by 8 on both sides

y = -5

Alex777 [14]3 years ago
4 0

Answer:

\boxed{y=-5}

\boxed{-5=y}

Step-by-step explanation:

Division property of equality- is a dividing both sides of an equation by the same non-zero number it does not change the equation.

a÷c=b÷c for c≠0

Checking a solution.

1. First you had to rewrite the original equation

2. Then you substitute the value for the variable

3. Finally simplify.

First you had to divide by eight from both sides of an equation form.

\frac{8y}{8}= \frac{-40}{8}

-40/8=-5

40/5=8

8*5=40

5*8=40

Final answer: \boxed{y=-5}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

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Find an upper limit for the zeroes 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0
erik [133]

<u>Answer-</u>

2 is the upper limit for the zeros.

<u>Solution-</u>

The given function f(x) is,

2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

For calculating the zeros,

\Rightarrow f(x)=0

\Rightarrow 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

\Rightarrow 2x^4-4x^3-3x^3+6x^2-2x^2+ 4x+3x-6=0

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\Rightarrow (x-2)(x^2-1)(2x-3)=0

\Rightarrow (x-2)(x+1)(x-1)(2x-3)=0

\Rightarrow x-2=0,\ x+1=0,\ x-1=0,\ 2x-3=0

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