The range of the given function is represented by {-6,-4,2}.
<h3>Domain and Range</h3>
The domain of a function is the set of input values for which the function is real and defined. In the other words, when you define the domain, you are indicating for which values x the function is real and defined.
While the domain is related to the values of x, the range is related to the possible values of y that the function can have.
Here, you need to replace the given domain values in the equation: f(x)=x-4. The question gives that the domain is represented by: -2 ,0 ,2 .
Thus,
For x=-2, you have:
f(x)= x-4
f(x)= -2-4
f(x)= -6
For x=0, you have:
f(x)= 0-4
f(x)= 0-4
f(x)= -4
For x=2, you have:
f(x)= x-4
f(x)= 2-4
f(x)= -2
Therefore, the range of the given function is {-6,-4,2}
Learn more about the range here:
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Well alternate angles are congruent, so that means they would both have the same measurement.
If you’re talking about equations with an angle then make the equations equal each other and solve. :)
Answer:
Enterprise charges more for a 6 day rental. ($284 for Hertz and $294 for Enterprise). Avery would save $4 if he rented with Hertz for 4 days.
Step-by-step explanation:
H = Hertz
E = Enterprise
x = Days rented
T = Total cost for x days, in $
<u>Hertz:</u> TH = 42x + 32
<u>Enterprise: </u> TE= 45x + 24
====================
6 Day Rental:
TH = 42*(6) + 32, = $284
TE = 45*(6) + 24 = $294
4 Day Rental:
TH = 42*(4) + 32, = $200
TE = 45*(4) + 24 = $204
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Answer:
The correct option D.
Step-by-step explanation:
The given function is
Where f(d) is the height of the ball at horizontal distance d.
Put f(d)=0, to find the distance where the ball touch the ground.
Quadratic formula:
Using the quadratic formula we get
Therefore the ball is in air between d=-0.146 to d=9.146.
The distance can not be negative, therefore the ball remains in the air between d=0 to d=9.146.
Therefore the correct option is D.
