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nataly862011 [7]
3 years ago
6

The range of y= 2/3 sin x for pi < x < 3pi/2 is ___?

Mathematics
1 answer:
victus00 [196]3 years ago
5 0

Answer:

-2/3 < y < 0

Step-by-step explanation:

y = Asin(x)

Edit*

There's a node (y=0) at pi for sine wave. At 3/2pi will be the min. So range goes from -2/3 to 0

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5 + 8s = 15 + 3s
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Can someone help me with this one
LekaFEV [45]

A= 108 centimeters sqaured if you are on oddeseyware thats the correct answer


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In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro
VladimirAG [237]

Answer:

Margin of error  for a 95% of confidence intervals is 0.261

Step-by-step explanation:

<u>Step1:-</u>

 Sample n = 81 business students over a one-week period.

 Given the population standard deviation is 1.2 hours

 Confidence level of significance = 0.95

 Zₐ = 1.96

Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }

Given n=81 , σ =1.2 and  Zₐ = 1.96

<u>Step2:-</u>

<u />Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }<u />

<u />Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }<u />

On calculating , we get

Margin of error = 0.261

<u>Conclusion:-</u>

Margin of error  for a 95% of confidence intervals is 0.261

<u />

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3 years ago
Where the image has the opposite orientation as the preimage
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BigorU [14]

The volume of the slice is 40 in³. The volume of the remaining cake would be 197.014 in³.

<h3>What is a regular hexagon?</h3>

A regular hexagon can be defined as a closed shape consisting of six equal sides and six equal angles.

Here we have two regular hexagons

one top small hexagon cake with a side of length = 3 in, height = 3 in

One big hexagon cake, side of length = 4 in, Height = 4 in

A slice cut such that it removes a side segment is equivalent to an equilateral triangle with a side

length = length of hexagon side

The length of the side of the removed equilateral triangle side

Top small cake slice triangle side = 3 in.

Area of surface of small slice = 1/2 x b x h = 1/2 x 3 x 3 x sin 60

                                                = 9√3/ 4

The volume of a small slice  

=  Area of surface small slice × Height of small cake

= 9√3/ 4  x 3

= 11. 69

Big cake slice triangle side = 4 in.

Area of the surface of big slice = 1/2 x 4 x 4 x sin 60

                                                    = 4√3

The volume of big slice =  Area of the surface of big slice × Height of big slice

= 16√3

= 28

The total volume of slice = Volume of small slice + Volume of big slice

Total volume of slice = 12 in³ +28 in³ = 40 in³

For the small cake,

the remaining volume = 5 x 11.69 = 58.45

For the big cake

the remaining volume = 5 x 27.71 = 138.56

Total volume remaining cake

= 58.45 in³ + 138.56 in³ = 197.014 in³

a = Length of side

h = Height of hexagon

The volume of each slice is,

= a^2 x h x √3/4

For the small cake, we have

a = 3 in.

h = 3 in.

The volume of small slice = a^2 x h x √3/4

                                   = 9 x 3 x √3/4

                                   = 27√3/4

For the big cake, we have

a = 4 in.

h = 4 in.

Volume of big slice =  a^2 x h x √3/4

                                = 16 √3

The total volume of slice = Volume of small slice + Volume of a big slice

Total volume of slice = 27√3/4 + 16 √3

The total volume of the slice = 39404 in³.

Learn more about hexagon;

brainly.com/question/16025389

#SPJ1

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