The answer for this is 10
So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
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3x +2y
A =xy = 6,000,000
y = 6,000, 000/x
L = 2x + 12,000,000/x
3- (12,000,000/x^2) = 0
3 = 12, 000,000/x^2
sqrt x^2 = sqrt 4,000,000
x = 2,000 and y = 3,000 <span>
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all of those r correct :)
Yes if u can multiply 10 by 1000 then it is a multiplication fact
