9:
-q^2 - r^2 + 3s
-9^2 - -6^2 + 3(-20)
-9^2 = -9 * -9 = 81
81 - -6^2 + 3(-20)
-6^2 = -6 * -6 = 36
81 - 36 + 3(-20)
3(-20) = -60
81 - 36 + -60
81 + 36 = 117
117 + (-60)
117 - 60= 57
57
10:
3| x + y |^2 - (xy)^2
3| 3 + -5 |^2 - (3-5)^2
(3-5) = 2
3| 3 + -5 |^2 - 2^2
|3 + -5| = 8
3|8|^2 - 2^2
8 * 8 = 64
3(64) - 2^2
2^2 = 2*2 = 4
3(64) - 4
3*64 = 192
192 - 4 = 188
188
11:
2x^2 - 5xy - y^3
2(-3)^2 - 5(-3-2) - -2^3
(-3-2) = -5
2(-3)^2 - 5(-5) - -2^3
-3^2 = -3 * -3 = -9
2(-9) - 5(-5) - -2^3
2^3 = 2 * 2 * 2 = 8
2(-9) - 5(-5) - 8
18 - 5(-5) - 8
5(-5) = -25
18 - (-25) - 8
18 + 25 - 8
18 + 25 = 43
43 - 8 = 35
35
12: -a^2 + 7b^4 -2c^3
—4^2 + 7(-2)^4 - 2(-3)^3
4^2 + 7(-2)^4 - 2(-3)^3
4 * 4 = 16
16 + 7(-2)^4 - 2(-3)^3
-2 * -2 * -2 * -2 = 16
16 + 7(16) - 2(-3)^3
-3 * -3 * -3 = -27
16 + 7(16) - 2(-27)
7 * 16 = 112
16 + 112 - 2(-27)
2 * -27 = -54
16 + 112 - -54
16 + 112 + 54
112 + 16 = 128
128 + 54 = 182
182
Answer:
range {3, 5, 6, 7 }
Step-by-step explanation:
to find the range substitute each value of x from the domain into f(x)
f(- 3) = -(- 3) + 4 = 3 + 4 = 7
f(- 2) = - (- 2 + 4 = 2 + 4 = 6
f(- 1) = - (- 1) + 4 = 1 + 4 = 5
f(1) = - 1 + 4 = 3
range y ∈ { 3, 5, 6, 7 }
The containers must be spheres of radius = 6.2cm
<h3>
How to minimize the surface area for the containers?</h3>
We know that the shape that minimizes the area for a fixed volume is the sphere.
Here, we want to get spheres of a volume of 1 liter. Where:
1 L = 1000 cm³
And remember that the volume of a sphere of radius R is:
Then we must solve:
![V = \frac{4}{3}*3.14*R^3 = 1000cm^3\\\\R =\sqrt[3]{ (1000cm^3*\frac{3}{4*3.14} )} = 6.2cm](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%2A3.14%2AR%5E3%20%3D%201000cm%5E3%5C%5C%5C%5CR%20%3D%5Csqrt%5B3%5D%7B%20%20%281000cm%5E3%2A%5Cfrac%7B3%7D%7B4%2A3.14%7D%20%29%7D%20%3D%206.2cm)
The containers must be spheres of radius = 6.2cm
If you want to learn more about volume:
brainly.com/question/1972490
#SPJ1
It’s either A or C I would pick A even though they don’t really make sense.
