3 years ago

Find the coordinates of the midpoint of HX (SHOW YOUR WORK) H(0,0),X(8,4)

Mathematics

1 answer:

prisoha [69]3 years ago

7 0

Y = mx + c
y = 0.5x
y = 0.5*4 = 2
(4,2)

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Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = $\frac{3}{4}$ ,

$q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28$

= $6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28$

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= $-\frac{833}{32}$ ≠ 0

Therefore, Yuri is not correct. x = $\frac{3}{4}$ can not be a root of the given expression.

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