Part 1:
We are going to divide.
18 ÷ 2/5
18/1 * 5/2
90/2
[ 45 pieces ] can be cut.
Part 2:
We are going to divide.
5 1/5 ÷ 1 4/10
26/5 ÷ 14/10
26/5 * 10/14
260/70
3.7
Note that we need FULL pieces so we are going to round down.
3.7 -> 3
Therefore, the answer is [ B.) 3 ]
Best of Luck!
Answer:
The passenger train is moving at 45 miles per hour
Step-by-step explanation:
Let the amount of time it took the two trains to travel the distance = t.
Since the two trains traveled the distance at the same time,
Rate of the passenger train =
Rate of the freight train =
<em>Where t is in hours.</em>
From the problem, we can see that the rate of the freight train was 15 miles per hour slower than the rate of the passenger train. Mathematically, we can represent this as
from the above equation, we can now get our value for t as
We have our time of travel for the two trains as 4 hours.
The rate of the passenger train can now be calculated by 180/4 = 45 miles per hour
Answer:
no
Step-by-step explanation:
use substitution
if (x,y)=(1,1)
7(1)+7(1)>14 ?
7+7>14 ?
14>14 X
the answer is no because 14 is not greater than 14, 14 is equal to 14 so this inequality is not true with (1,1)
Equation describes a sloping line. For any
equation ax+by+c = 0, slope is .<span>X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 30/5 = 6.Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 30/-3 = -10.Slope is -5/-3 = 1.66666666666667.<span> Equation in slope-intercept form: y=1.66666666666667*x+-10.</span></span>
Answer:
12.7m
Step-by-step explanation:
The equation for motion to be used to find how far the water travels is
xf = xi + Vix(t) + 1/2axt^2
xf = 0 + ViCos α(t) + 0
xf = ViCosα(t)
xf = 12 Cos 30°(t)
xf = (6√3)t
To find the total times we will use the vertical displacement equation
yf = yi + Viy(t) + 1/2ayt^2
0 = 0 + ViSinα(t) + (1/2 * (-9.8)t^2)
0 = 12Sin30°(t) - 4.9t^2
4.9t^2 = 12Sin30°(t)
4.9t^2 = 6t
Divide through by t
4.9t = 6
t = 6/4.9
t = 1.22secs
Put t = 1.22 into (6√3)t
xf = 6√3 * 1.22
xf = 12.7m