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2 years ago

-2 times g(4) when g(x) =-x squared+(4x)-11

Mathematics

1 answer:

andrezito [222]2 years ago

3 0

Answer:

+22

Step-by-step explanation:

Given g(x) = -x^2 + 4x - 11, g(4) is -(4)^2 + 4(4) - 11, or just -11.

Then -2 times g(4) = -2(-11) = +22

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The hypotenuse of a right triangle is √18 units. what are the lengths of the legs of the triangle? How many different answers ca

storchak [24]

Since a right triangle has special rules to it such that the hypotenuse squared equals the sum of the squares of the other 2 sides. In other words, if the hypotenuse = c, and the 2 smaller sides are a and b, then:
${c}^{2} = {a}^{2} + {b}^{2}$
Solving for c (hypotenuse), we get:
$\sqrt{({c}^{2})} = \sqrt{({a}^{2}+{b}^{2} )} \\ c = \sqrt{({a}^{2}+{b}^{2} )}$
Therefore c is the root of the square of the other sides. So by having root18, it's like saying:
$\sqrt{18} = \sqrt{({a}^{2} + {b}^{2} )} \\ 18 = {a}^{2} + {b}^{2}$
Getting rid of the square root, so sides a and b must have their squares total 18:
the only squares < 18 are: 16 (4×4), 9 (3×3), 4 (2×2), and 1 (1×1)
of those above added in any order of two of them, only 16+4
$18 = 17 + 1 - - > \sqrt{17} \: and \: 1 \\ 18 = 16 + 2 - - > \sqrt{16} \: and \: \sqrt{2} \\ ... \: 4 \: and \: \sqrt{2} \\ 18 = 15 + 3 - - > \sqrt{15} \: and \: \sqrt{3}$
$18 = 14 + 4 - - > \sqrt{14} \: and \: \sqrt{4} \\ ... \sqrt{14} \: and \: 2 \\ 18 = 13 + 5 - - > \sqrt{13} \: and \: \sqrt{5} \\ 18 = 12+ 6 - - > \sqrt{12} \: and \: \sqrt{6}$
$18 = 11 + 7 - - > \sqrt{11} \: and \: \sqrt{7} \\ 18 = 10 + 8 - - > \sqrt{10} \: and \: \sqrt{8} \\ ... \sqrt{10} \: and \: 2 \sqrt{2} \\ 18 = 9 + 9 - - > \sqrt{9} = 3 \: and \: 3$
I HOPE THAT IS ALONG THE LINE THAT WAS ASKED FOR!!! :-D

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2 years ago

How much will a person pay for 7.5 pounds of bananas at a price of $2.07 per pound?

igomit [66]

Answer:

$15.57

Step-by-step explanation:

2.07 times 7.50 = $15.57!

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2 years ago

Pretty please helppplp!!!!!!

Alika [10]

Since the x's both are to a power and have exponents outside of the parenthesis, we multiply the inner exponent by the outer exponent.

x^-150 / x^-144

Then, we need to move the bottom term to the top so that we have no negative exponents. Now, we are technically subtracting, but subtracting a negative is the same thing as adding.

x^(-150 + 144)

x^-6

Hope this helps!

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2 years ago

Read 2 more answers

Solve the compound inequality |3x-9|≤15 and |2x-3|≥5. Give answer in interval notation.

laila [671]

Answer:

The solution of |3x-9|≤15 is [-2;8] and the solution |2x-3|≥5 of is (-∞,2] ∪ [8,∞)

Step-by-step explanation:

When solving absolute value inequalities, there are two cases to consider.

Case 1: The expression within the absolute value symbols is positive.

Case 2: The expression within the absolute value symbols is negative.

The solution is the intersection of the solutions of these two cases.

In other words, for any real numbers a and b,

if |a|> b then a>b or a<-b
if |a|< b then a<b or a>-b

So, being |3x-9|≤15

Solving: 3x-9 ≤ 15

3x ≤15 + 9

3x ≤24

x ≤24÷3

x≤8

or 3x-9 ≥ -15

3x ≥-15 +9

3x ≥-6

x ≥ (-6)÷3

x ≥ -2

The solution is made up of all the intervals that make the inequality true. Expressing the solution as an interval: [-2;8]

So, being |2x-3|≥5

Solving: 2x-3 ≥ 5

2x ≥ 5 + 3

2x ≥8

x ≥8÷2

x≥8

or 2x-3 ≤ -5

2x ≤-5 +3

2x ≤-2

x ≤ (-2)÷2

x ≤ -2

Expressing the solution as an interval: (-∞,2] ∪ [8,∞)

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2 years ago

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dlinn [17]

Answer:

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Step-by-step explanation:

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