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Elenna [48]
3 years ago
10

-2 times g(4) when g(x) =-x squared+(4x)-11

Mathematics
1 answer:
andrezito [222]3 years ago
3 0

Answer:

+22

Step-by-step explanation:

Given g(x) = -x^2 + 4x - 11, g(4) is -(4)^2 + 4(4) - 11, or just -11.

Then -2 times g(4) = -2(-11) = +22

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Substitute the first equation into the second equation, since y is already by itself.

2x - 5(-1 + 3/8x) = 6

2x + 5 - 15/8x = 6

2x - 15/8x = 1

16/8x - 15/8x = 1

1/8x = 1 Multiply 8 on both sides to get x by itself

x = 8


Plug x into either of the equations.

y = -1 + 3/8(8)

y = -1 + 3

y = 2


2(8) - 5y = 6

16 - 5y = 6

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8 0
3 years ago
Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located
arsen [322]
Check the picture below.

\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------

\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}

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3 years ago
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erastova [34]

Answer:

Step-by-step explanation:

27,33

9*3 is 27

11*3 is 33

33-27 is 6

i only have one, sorry!

8 0
3 years ago
Read 2 more answers
The probability that a visitor to an animal shelter will adopt a dog is .20. out of nine visits, what is the probability that at
lana66690 [7]
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D = number of dogs washed
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d = (60 - 5c) / 7.50
The 7.50 should be underneath the brackets 
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