Answer:
Step-by-step explanation:
total points obtained=141+87+81+91=400
total possible points=150+100+100+100=450
1.
% points obtained=(400/450)×100≈88.89
Jade did not secured more than 88.89 % marks.
2. can't read properly
6 / 5/9
First turn 5/9 into decimal form.
5 / 9 = 0.55555555555555555555555555555556
Then divide 6 by 0.55555555555555555555555555555556
6 / 0.55555555555555555555555555555556 = 10.8 or 10 8/10 or 10 4/5
Give brainliest if this helped!
Answer:
Step-by-step explanation:
Hello,
We know that
![|x|=\begin{cases}x & \text{if } x\geq 0 \\ -x & \text{if } x](https://tex.z-dn.net/?f=%7Cx%7C%3D%5Cbegin%7Bcases%7Dx%20%26%20%5Ctext%7Bif%20%7D%20x%5Cgeq%200%20%5C%5C%20-x%20%26%20%5Ctext%7Bif%20%7D%20x%3C0%20%5Cend%7Bcases%7D)
So we need to take into account two cases
Case 1 - ![x-3\geq 0 x\geq 3](https://tex.z-dn.net/?f=x-3%5Cgeq%200%3C%3D%3E%20x%5Cgeq%203)
Then, |x-3|=x-3
||x-3|-2|=|x-3-2|=|x-5|
<em>Either </em>x-5 is positive and then |x-5|=x-5 and
<em>Or</em> x-5 is negative and then, |x-5|=-x+5
![|x-5|\leq 1-x+5\leq 14\leq x](https://tex.z-dn.net/?f=%7Cx-5%7C%5Cleq%201%3C%3D%3E-x%2B5%5Cleq%201%3C%3D%3E4%5Cleq%20x)
So the solution is [4;6]
Case 2 - ![x-3< 0 x< 3](https://tex.z-dn.net/?f=x-3%3C%200%3C%3D%3E%20x%3C%203)
Then, |x-3|=-x+3
||x-3|-2|=|-x+3-2|=|-x+1|
Either -x+1 is positive and then |-x+1|=-x+1 and
Or -x+1 is negative and then, |-x+1|=x-1
![|-x+1|\leq 1x-1\leq 1x\leq 2](https://tex.z-dn.net/?f=%7C-x%2B1%7C%5Cleq%201%3C%3D%3Ex-1%5Cleq%201%3C%3D%3Ex%5Cleq%202)
So the solution is [0;2]
Conclusion
The solution is [0;2]∪[4;6]
Thanks
{(9)(9/256)}^3/2=
(81/256)^3/2=
0.031676352/2=
0.015838176