Answer:
Step-by-step explanation:
Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.
The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.
The system is
6h + 1d = 40
4h + 3d = 36
The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,
1d = 40 - 6h.
Now that we know what d equals, we can sub it into the second equation where we see a d. In order,
4h + 3d = 36 becomes
4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!
4h + 120 - 18h = 36 and
-14h = -84 so
h = 6.
That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:
1d = 40 - 6(6) and
d = 40 - 36 so
d = 4.
That means that each duck costs $4.
Answer:
Step-by-step explanation:
hello :
y-3=-2(x+5)
y - intercept when : x=0 : y-3 =-2(0+5)
y-3 =-10
y = - 7
Answer:
x = - 
Step-by-step explanation:
(x - 3) - 5 =
(x - 1)
Multiply through by 8 to clear the fractions
6(x - 3) - 40 = x - 1 ← distribute parenthesis and simplify left side
6x - 18 - 40 = x - 1
6x - 58 = x - 1 ( subtract x from both sides )
5x - 58 = - 1 ( add 58 to both sides )
5x = - 57 ( divide both sides by 5 )
x = - 
Answer:
y=-3/5(x+5)+4
Step-by-step explanation:
y=m(x-h)+k
y=-3/5(x+5)+4
Rational Number are set of numbers that can be written as a/b where a and b are integers, but b is not equal to 0; an integer or a fraction; for example: 6 can be expressed as 6/1 and 0.5 can be expressed as 1/2.