To calculate the range of the given function we first need to calculate for the inverse of the function;
y=sqrt(x)-5
this can be written as:
y+5=sqrt(x)
From the above equation we can conclude that we can get the squaring of all values of x such that:
x≥-5
otherwise we won't get any square root since the square roots of negative numbers will complex numbers;
thus we conclude that the range of the function is {y∈R: y≥-5}
since -4 is included in this set, then our answer is option [A]
Answer:
-1
Step-by-step explanation:
hope that helps :)
Answer:
C. AC/BC = DF/EF
Step-by-step explanation:
Hi en that ∆ABC ~ ∆DEF, the corresponding sides of ∆ABC and ∆DEF would be proportional to each other.
AB corresponds to DE
AC corresponds to DF
BC corresponds to EF
Therefore,
hypotenuse over one of the leg of ∆ABC = hypotenuse over one of the corresponding legs of ∆DEF, which is:
AC/BC = DF/EF
Answer:
1. positive
2. negative
Step-by-step explanation:
When I was taught how this concept worked, my teacher used a metaphor to help us figure out the sign of a quotient of any positive or negative integer.
He told us that you could imagine the first sign being a good or a bad person, negative sign meaning bad, positive sign meaning good. the second integer in the multiplication would be whether that person (good or bad) was leaving or entering your town.
then, to figure out the sign of the quotient, you just thought about whether that scenario would be a bad thing or a good thing.
I know it probably seems a little confusing, but it helps to see an example.
-9 x 3 = ?
so we'd say that the scenario for that equation would be that a bad person was entering your town. that would be a bad thing, therefore the outcome would be a negative number.
-9 x 3 = -27
lets do the reverse!
5 x -8 = ?
the scenario for this equation would be a good person (the positive number) leaving your town (the negative number). That would generally be considered a bad thing, giving us the answer of a negative number again.
5 x -8 = -40
you can use this technique to answer your questions as well, by thinking through the possible scenarios for a positive-positive equation or a negative-negative equation, then looking at the ones we already went over for the second response question.
This works with all integer multiplication, so i thought id share what helps me!