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3 years ago

Find the exact value of the expression cos10°cos20°-sin10°sin20° Please Help

Mathematics

1 answer:

Svet_ta [14]3 years ago

5 0

Cos10 cos20 -sin10 sin20 = cos(10+20) = cos30 = √3/2

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Which of the following expressions are equivalent to 3(2x – 8)? Select all that apply.

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Answer:

Step-by-step explanation:

3(2x – 8)

3(2x) + 3(-8)

6x + -24

6x - 24

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2 years ago

What is the answer to this equation 5×.4x=10

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3 years ago

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Evaluate each expression. Determine if the final simplified form of the expression is positive or negative -42 (-4)2 42

Sati [7]

Answer:

Given the expression:

$-4^2$

we know:

$4^2 = 4 \times 4 = 16$

then;

$-4^2 = -16$

Therefore, the value of expression $-4^2$ is -16 i.e negative.

$(-4)^2$

we know:

$4^2 = 4 \times 4 = 16$

$(-1)^2 = 1$

then;

$(-4)^2 = (-1)^2 \cdot (4)^2= 16$

Therefore, the expression $(-4)^2$ is 16 i.e Positive.

$4^2$

we know:

$4^2 = 4 \times 4 = 16$

then;

$4^2 = 16$

Therefore, the expression $4^2$ is 16 i.e Positive.

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2 years ago

According to the graph, what is the experimental probability of selecting the letter T?

valentina_108 [34]

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2 years ago

Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg lesss strawberries in the morning tha in the afte

Tpy6a [65]

Answer:

$3\frac{13}{20}=3.65$ kg.

Step-by-step explanation:

Let S be amount of strawberries picked in the afternoon.

We have been given that Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg less strawberries in the morning than in the afternoon and the strawberries picked in morning are $2\frac{1}{4}$ kg.

To find the amount of strawberries picked by Sheldon in the afternoon we will add $2\frac{1}{4}$ and $1\frac{2}{5}$ :

$S= 2\frac{1}{4}+1\frac{2}{5}$

Upon converting our given mixed fractions into improper fraction we will get,

$S= \frac{9}{4}+\frac{7}{5}$

Now let us have a common denominator.

$S=\frac{9*5}{4*5}+\frac{7*4}{5*4}$

$S=\frac{45}{20}+\frac{28}{20}$

$S=\frac{45+28}{20}$

$S=\frac{73}{20}$

$S=3\frac{13}{20}$

$S=3.65$

Therefore, Sheldon picked $3\frac{13}{20}=3.65$ kg of strawberries in the afternoon.

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3 years ago