Split
into two component segments,
and
, parameterized by


respectively, with
, where
.
We have


where 
so the line integral becomes



Answer:
The discount is the same.
Step-by-step explanation:
We need to find the ratios of both discounts.
41/50 = 61.5/75
If the question is True, this means that the ratios should be the same. So we have to cross multiply to find the answer.
75*41 = 50*61.5 = 3075
These two multiplication problems both equal 3075. Since the ratios are equal, the discounts are also equal.
F ( x ) = 3 sim x + 3 cos x
f ` ( x ) = 3 cos x - 3 sin x
f `` ( x ) = - 3 sin x - 3 cos x = - 3 ( sin x + cos x )
The inflection points:
- 3 ( sin x + cos x ) = 0
sin x + cos x = 0
sin x = - cos x / : cos x
tan x = - 1
x 1 = 3π / 4
x 2 = 7π / 4
The function is concave up when f``(x) > 0
- 3( sin x+ cos x ) > 0
sin x + cos x < 0
tan x < - 1
f is concave up for:
x ∈ ( π/2, 3π/4 ) ∪ ( 3π/2, 7π/4)
f is concave down for:
x ∈ ( 0, π/2 ) ∪ ( 3π / 4, 3π/2 ) ∪ ( 7π / 4, 2 π ).
A. is 10! you multiply the scale (2.5) times the length (4)
b. is 6, you divide 15 by 2.5
c. is 5. you do what you did with a but with 2 inches instead of 4
d. is 1.5 you divide 378 by 250
C because that is the point at which x is -9 and y is 8