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Pavlova-9 [17]
4 years ago
9

The sum of partial products is equal to the final product?

Mathematics
1 answer:
Shkiper50 [21]4 years ago
8 0
The sum of partial product is not always equal to a final product

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6) Qual número deve ser acrescentado a expressão x² - 12x, para que se obtenha um trinômio quadrado perfeito? * 6 5 12 10
Serga [27]

Respuesta:

36

Explicación paso a paso:

Para completar el cuadrado tendremos que sumar la mitad del cuadrado del coeficiente de x a la expresión;

Coeficiente de x = -12

Mitad del coeficiente = (-12/2) = -6

Tomando el cuadrado del resultado = (-6) ^ 2 = 36

Por lo tanto, el número que se debe sumar para obtener un cuadrado perfecto es 36.

7 0
3 years ago
What is the volume of a right circular cylinder with a radius of 4 m and a height of 4 m?
katovenus [111]

Answer:

V≈201.06m³

Step-by-step explanation:

V=πr2h=π·42·4≈201.06193m³

plz mark me as brainliest if this helped :)

7 0
4 years ago
Read 2 more answers
Please help me solve this problem ASAP
DiKsa [7]

\bold{\huge{\blue{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • <u>The </u><u>right </u><u>angled </u><u>below </u><u>is </u><u>formed </u><u>by </u><u>3</u><u> </u><u>squares </u><u>A</u><u>, </u><u> </u><u>B </u><u>and </u><u>C</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>B</u><u> </u><u>has </u><u>an </u><u>area </u><u>of </u><u>1</u><u>4</u><u>4</u><u> </u><u>inches </u><u>²</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>C </u><u>has </u><u>an </u><u>of </u><u>1</u><u>6</u><u>9</u><u> </u><u>inches </u><u>²</u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u><u>A</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

The right angled triangle is formed by 3 squares

<u>We </u><u>have</u><u>, </u>

  • Area of square B is 144 inches²
  • Area of square C is 169 inches²

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{ Area \: of \: square =  Side × Side }

Let the side of square B be x

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 144 =  x × x }

\sf{ 144 =  x² }

\sf{ x = √144}

\bold{\red{ x = 12\: inches }}

Thus, The dimension of square B is 12 inches

<h3><u>Now, </u></h3>

Area of square C = 169 inches

Let the side of square C be y

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 169 =  y × y }

\sf{ 169 =  y² }

\sf{ y = √169}

\bold{\green{ y = 13\: inches }}

Thus, The dimension of square C is 13 inches.

<h3><u>Now, </u></h3>

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3><u>Therefore</u><u>, </u><u>By </u><u>using </u><u>Pythagoras </u><u>theorem</u><u>, </u></h3>

  • <u>The </u><u>sum </u><u>of </u><u>squares </u><u>of </u><u>base </u><u>and </u><u>perpendicular </u><u>height </u><u>equal </u><u>to </u><u>the </u><u>square </u><u>of </u><u>hypotenuse </u>

<u>That </u><u>is</u><u>, </u>

\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}

<u>Here</u><u>, </u>

  • Base = x = 12 inches
  • Perpendicular = z
  • Hypotenuse = y = 13 inches

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ (z)² + (x)² = (y)² }

\sf{ (z)² + (12)² = (169)² }

\sf{ (z)² + 144 = 169}

\sf{ (z)² = 169 - 144 }

\sf{ (z)² = 25}

\bold{\blue{ z = 5 }}

Thus, The dimensions of square A is 5 inches

<h3><u>Therefore</u><u>,</u></h3>

Area of square

\sf{ = Side × Side }

\sf{ = 5 × 5  }

\bold{\orange{ = 25\: inches }}

Hence, The area of square A is 25 inches.

6 0
2 years ago
So my teacher wants me to Evaluate the expression when x=20 and z=7 <br> z times x=<br> HELP PLEASE
stellarik [79]

Answer:

subsitute x for 20 then subsitute z of 7 then solve.

Step-by-step explanation:

8 0
3 years ago
Use synthetic division to determine whether the number k is an upper or lower bound (as specified) for the real zeros of the fun
anastassius [24]

Answer:

Yes,  k is lower bound for the real zeros of the function.

Step-by-step explanation:

Lower Bound Theorem:

If you divide a polynomial function f(x) by (x - k), where k < 0, using synthetic division and this yields alternating signs, then k is a lower bound to the real roots of the equation f(x) = 0.

Given;

4x³ - 2x² + 2x + 4

k = -1

synthetic division;

-1 ]    4       -2        2        4

        ↓         -4        6       -8

---------------------------------------------

        4         -6       8          -4  

(the result has alternating signs, hence k is lower bound)

Thus, k is lower bound for the real zeros of the function.

5 0
3 years ago
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