The two non negative real numbers with a sum of 64 that have the largest possible product are; 32 and 32.
<h3>How do we solve the nonnegative real numbers?</h3>
Let the two numbers be x and y.
Thus, if their sum is 64, then we have;
x + y = 64
y = 64 - x
Their product will be;
P = xy
Putting (64 - x) for y in the product equation we have;
P = (64 - x)x
P = 64x - x²
Since the product is maximum, let us find the derivative;
P'(x) = 64 - 2x
At P'(x) = 0, we have;
64 - 2x = 0
2x = 64
x = 64/2
x = 32
Thus; y = 64 - 32
y = 32
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<span>(6/x²)² (x/2)⁴ = (36/x⁴) * (x⁴ / 16) = (36/16) = 9/4
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Answer:
C. (-5,-1)
E. (10,2)
F. (15,3)
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<u><em>hope it helps...</em></u>
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Answer:
1, 2 and 3
Step-by-step explanation:
Let
t -----> the number of hours the job takes
C(t) -----> the total cost for the service
we have
This is the equation of a line in slope intercept form
where
The slope m is equal to 
The y-intercept is the point (0,95) ---> The cost is $95 for the value of t equal zero (fee)
therefore
<u><em>The statements that are true</em></u>
1 a house call fee costs $95
2 the plumber charges $125 per hour
3 the number of hours the job takes is represented by t
Answer:
f(x) = 4x4 – 7x2 + x + 25 f(x) = 9x4
Step-by-step explanation:
Because it has to be this one
