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lesya [120]
3 years ago
12

What is the gcf of the terms of the polynomial?​

Mathematics
2 answers:
Naily [24]3 years ago
8 0

Answer:

The GCF is 3x^3.

Step-by-step explanation:

24x^4y + 21x^3

GCF of 24 and 21 is 3.

GCF of x^4y and x^3 is x^3.

Vikentia [17]3 years ago
6 0
The gcf would be 3x^3
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Suppose that you flip a coin 13 times. What is the probability that you achieve at least 5 tails?
wariber [46]
Heads, or tails. It's 1/2 a chance, because either way you will either land heads or tails. It would be a probability of 1-(1/2)^5. Can you solve that?
5 0
3 years ago
What is the value of the expression below?<br> 32^3/5<br> O A. 6/5<br> B. 6<br> O c. 96/5<br> O D. 8
Hoochie [10]

Answer:

D. 8

Step-by-step explanation:

32^(3/5) is the same as \sqrt[5]{32}^3.

 \sqrt[5]{32} = 2 because 2^5=32

2^3 = 8

6 0
2 years ago
Read 2 more answers
Pre-Calc: Find all the zeros of the function.
uysha [10]

The zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i and the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

<h3>What are polynomial expressions?</h3>

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

<h3>How to determine the zeros of the polynomial?</h3>

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Set the equation to 0

So, we have

(5y - 4)(5y + 4)(25y^2 + 16) = 0

Expand the equation

So, we have

5y - 4 = 0, 5y + 4 = 0 and 25y^2 + 16 = 0

This gives

5y = 4, 5y = -4 and 25y^2 = -16

Solve the factors of the equation

So, we have

y = 4/5, y = -4/5 and y = ±4/5√i

Hence, the zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i

How to write the polynomial as a product of the linear factors?

In (a), we have

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Hence, the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Read more about polynomial at

brainly.com/question/17517586

#SPJ1

5 0
1 year ago
Name the two input device​
nikitadnepr [17]

Answer:

keyboard and mouse are two examples of input device

8 0
3 years ago
Evaluate N= -3.3 - n x n
photoshop1234 [79]

Answer:kk

Step-by-step explanation:

8 0
3 years ago
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