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azamat
2 years ago
14

The initial population of bacteria in a lab test is 400. The number of bacteria doubles every 30 minutes. Predict the bacteria p

opulation at the end of three hours
Mathematics
1 answer:
vladimir1956 [14]2 years ago
6 0
25,600 will be the bacteria population after doubling every 30 minutes for 3 hours.
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Marina86 [1]

i don't have an answer sorry.

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3 years ago
Help with inequalities
max2010maxim [7]

Answer:

2(b - 9) \geqslant 26

Step-by-step explanation:

difference of a number and 9 means to subtract

b - 9

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2(b - 9)

at least is greater than or equal to

2(b - 9) \geqslant 26

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3 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
Solve triangle. round to the nearest tenth​
LUCKY_DIMON [66]

Answer:

37.5 ( i didn't round cause the answer looked simple already)

Step-by-step explanation:

formula for triangle is base x height divided by 1/2

Base(5) x Height(15) = 75 now divide by 1/2

75 divided by 1/2 = 37.5

(Could i have brainliest if i'm right?)

4 0
2 years ago
310 is the product of 106 and n​
lyudmila [28]

Answer:

Step-by-step explanation:

106n=310

n=300/106=150/53

6 0
3 years ago
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