1. To solve this problem you must sum the volume of the cone and the volume of the hemisphere. This means that the volumen of the prop is:
Vt=Vc+Vh
Vt is the volumen of the prop.
Vc is the volumen of the cone.
Vh is the volume of the hemisphere.
2. The volume of the cone (Vc) is:
Vc=1/3(πr²h)
r=9 in
h=14 in
π=3.14
4. Then, you have:
Vc=(3.14)(9 in)²(14 in)/3
Vc=3560.76 in³/3
Vc=1186.92
5. The volume of the hemisphere (Vh) is:
Vh=2/3(πr³)
π=3.14
r=9 in
6. Then, you have:
Vh=(2)(3.14)(9 in)³/3
Vh=4578.12 in³/3
Vh=1526.04 in³
7. Finally, the volumen of the prop (Vt) is:
Vt=Vc+Vh
Vt=1186.92 in³+1526.04 in³
Vt=2713.0 in³
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What is the volume of the prop?
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The volume of the prop is 2713.0 in³
Hththhththhthhththhthththht
the answer is 3,4
Well following the directions you have provided me I would say that Jen will have
3 Gallons of strawberries. Work: So the fraction 3/4 can be converted into decimals which is .75 and since she got that many in half and hour ( 30 minutes) we can do two set of .75 for each hour, after we do the math we end up with 4 sets in total of .75 since she had 2 hours to work.
Equation .75*4=3 I hope this helped you out!
Answer:
To know if Nicholas is correct
4(540π) inches³ ≥ 2304π inches³
Unfortunately, 2160π inches³ is less than 2304π inches³. This means Nicholas is absolutely wrong .4 times the volume of the cylindrical bucket is less than the volume of the spherical tank.
Step-by-step explanation:
The question wants you to look for the volume of the cylindrical bucket and the spherical bucket and know if 4 times the volume of the cylindrical bucket will fill the spherical tank.
volume of a cylinder = πr²h
where
r = 6 inches
h = 15 inches
volume of the cylinder bucket = πr²h
volume of the cylinder bucket= π × 6² × 15
volume of the cylinder bucket = π × 36 × 15
volume of the cylinder bucket = 540π inches³
volume of the spherical storage container
volume = 4/3πr³
r = 24/2 = 12 inches
volume = 4/3 × π × 12³
volume = 4/3 × π × 1728
volume = 6912π/3
volume = 2304π inches³
To know if Nicholas is correct 4(540π) inches³ ≥ 2304π inches³
Unfortunately, 2160π inches³ is less than 2304π inches³. This means Nicholas is absolutely wrong .4 times the volume of the cylindrical bucket is less than the volume of the spherical tank.
