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andriy [413]
2 years ago
7

On a standard circular 12-hour clock, the numerals 12 and 6 are opposite each other. On the planet Bajor, they use a circular te

n-hour clock with the numerals 1 to 10 equally spaced. What pair of opposite numerals on a Bajorian clock has a sum of 11?
Please add an explanation with your answer.
Mathematics
1 answer:
anastassius [24]2 years ago
7 0
Opposite Numbers and their Sums:

1+6=7
2+7=9
3+8=11
4+9=13
5+10=15

Because of this, the pair of opposite numbers are 3 and 8 if you want the pair that equal 11.
You might be interested in
three friends are in the same algebra class. Their scores on a recent test are three consecutive odd intergers whose sum is 279.
jasenka [17]
X= 1st integer
x+2= 2nd integer
x+4= 3rd integer

Add the integers together

x + (x + 2) + (x + 4)= 279
combine like terms
3x + 6= 279
subtract 6 from both sides
3x= 273
divide both sides by 3
x= 91 first integer

Substitute x=91 to find 2nd & 3rd integers

2nd Integer
=x+2
=91+2
=93

3rd Integer
=x+4
=91+4
=95

ANSWER: The three test scores are 91, 93 and 95.

Hope this helps! :)
7 0
3 years ago
9(x+2)= 5 - 2( x - 1 )
omeli [17]

We can use the distribution method for both sides:

9 (x+2) = 5 - 2( x - 1 )

9x + 18 = 5 -2x + 2

Move like terms to one side and combine:

9x + 2x = 5+2-18.

11x = -11

x = -1.

5 0
3 years ago
Read 2 more answers
The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0
3 years ago
Which statement about a rotation is true? A. Rotating a right trapezoid around its vertical axis will form a cone. B. Rotating a
yawa3891 [41]

Rotating a shape involves moving it in a circular way around its axis

The true statement about the rotation is (c) Rotating a right triangle around its vertical axis will form a cone.

<h3>How to determine the rotation?</h3>

When a two-dimensional shape such as triangles, trapezoid, square, rectangles, etc are rotated about their axes, the new shape formed is a three-dimensional shape

As a general rule, the rotation of a right triangle around its axis would form a cone.

Hence, the true statement about the rotation is (c)

Read more about rotation at:

brainly.com/question/4289712

3 0
2 years ago
28
posledela
<h3>answer:</h3>

u would have 7 each row

3 0
3 years ago
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