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DedPeter [7]
3 years ago
8

Select the correct answer.

Mathematics
1 answer:
masha68 [24]3 years ago
3 0

Answer:

what is your question here can you be more specific?

Step-by-step explanation:

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The graph shows the 2005 median income of some year-round workers and the number of years of school. Estimate the median income
xxTIMURxx [149]

Answer:20??

Step-by-step explanation:

4 0
3 years ago
Factorise fully 6a+10ab can someone do this
sashaice [31]

Answer:

Step-by-step explanation:

To factorize ,

6a+10ab

=2a(3+5b)    [ common 2a from both the terms]

4 0
3 years ago
Is there a difference between the 80th percentile and the top 80%?
Aleksandr [31]
<span>Actually, yes there is. Being in the 80th percentile means that you are smart than 80% of the people (i.e. out of 100 people, you would be smarter than 80 of them). However being in the top 80% means that you are a part of the 80 smartest people out that same 100. </span>
8 0
3 years ago
-10+5k^5 write in standard form
Yanka [14]

Answer:

Step-by-step explanation:

How to write numbers in standard form:

Write the first number 8.

Add a decimal point after it: 8.

Now count the number of digits after 8. There are 13 digits.

So, in standard form: 81 900 000 000 000 is 8.19 × 10¹³

7 0
2 years ago
Find the probability of drawing 3 Aces at random from a deck of 52 ordinary playing cards if the cards are:_________
Minchanka [31]

Answer:

A) 1/2197

B) 1/5525

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probability = Expected outcome/Total outcome.

Since there are 52 random cards in a deck of card, the total outcome will be 52.

a) Also in a deck of card, there are 4 aces. If we are to select 3 aces with replacement, this means that each time we pick up an ace from the card, it was returned.

Pr(drawing an ace) = 4/52

Pr(drawing 3 aces and replacing it) = 4/52 *4/52*4/52

Pr(drawing 3 aces and replacing it) = 64/140,608

Pr(drawing 3 aces and replacing it) = 1/2197

b) If we pick 3 aces without replacement then each time we pick an ace, the total number cards keeps reducing.

Pr(picking the first ace) = 4/52

Pr(picking the second ace without replacing) = 3/51 (Since we didn't replace the first one, the total ace in the deck of card will reduce to 3 and the total will be 51)

Pr(picking the third ace without replacing) = 2/50 (since we didn't replace the first two aces, the total ace in the deck of card will reduce to 2 and the total will be 50)

Pr(drawing 3 aces without replacement) =  4/52*3/51*2/50

Pr(drawing 3 aces without replacement) =  24/132,600

Pr(drawing 3 aces without replacement) = 1/5525

5 0
3 years ago
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