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kicyunya [14]
3 years ago
15

Can some on please help me I need it

Mathematics
1 answer:
SVEN [57.7K]3 years ago
4 0
-7+3x+7x = 7x+5
10x-7  = 7x+5
 -7x        -7x

3x-7 =  5
    +7    +7

3x = 12

x=4
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Circle V is shown. Line segments Y V and W V are radii. Tangents Y X and W X intersect at point X outside of the circle. The len
bagirrra123 [75]

Answer:

(C)90^\circ

Step-by-step explanation:

Theorem: The angle between a tangent and a radius is 90 degrees.

Given that

  • YV and WV are radii
  • YX and WX are tangent lines.

By the theorem stated above:

\angle VYX =90^\circ\\\angle VWX =90^\circ

We are told that Angle V is a right angle.

Therefore, in the quadrilateral VWXY

\angle VYX+\angle VWX+\angle V+ \angle X =360^\circ\\90^\circ+90^\circ+90^\circ+ \angle X =360^\circ\\270^\circ+ \angle X =360^\circ\\\angle X =360^\circ-270^\circ\\\angle X =90^\circ

The measure of circumscribed ∠X is 90 degrees.

7 0
3 years ago
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I need this help me
djverab [1.8K]

Step-by-step explanation:

the answer is 2/9

2/9 is .2222222 continuing

2/10 is 0.2

22/1000 is 0.022

2/8 is 0.25

6 0
3 years ago
Plz help its due tonight!!!!
Natalka [10]

Answer:

Domain is (infinity, infinity) so it would hit every single number of x. The range which is y would be greater than or equal to -3. Range starts at -3 and hits every number above that.

8 0
3 years ago
5.23 minus 2.1 write a story
lora16 [44]

Answer:

3.13

Step-by-step explanation:

There were 5.23 apples and 2.1 of them were eaten by bob. How many are left?

6 0
3 years ago
How do you work this out
Digiron [165]
Check the picture below.

notice, is just a circle inscribed in a square.

now for the first one, we know the diameter is 14, so the square is a 14x14, and the radius of that is half the diameter or 7.

now, if we get the area of the square, which includes the area of the circle, and THEN get the area of the circle and subtract it from the square's, what's leftover is the shaded section.

\bf \textit{area of a circle}\\\\ A=\pi r^2\\\\
-------------------------------\\\\
\stackrel{\textit{square's area}}{14\cdot 14}~-~\stackrel{\textit{circle's area}}{\pi 7^2}\implies 196-49\pi

now, for the one on the right-hand-side, the radius is 8, and square's area is 16x16,

\bf \stackrel{\textit{square's area}}{16\cdot 16}~-~\stackrel{\textit{circle's area}}{\pi 8^2}\implies 256-64\pi

5 0
4 years ago
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