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amid [387]
3 years ago
15

A boat heading out to sea starts out at Point A, at a horizontal distance of 804 feet from a lighthouse/the shore. From that poi

nt, the boat’s crew measures the angle of elevation to the lighthouse beacon-light from that point to be 12^∘ . At some later time, the crew measures the angle of elevation from point B to be 2^∘ . Find the distance from point A to point B. Round your answer to the nearest foot if necessary.
Mathematics
1 answer:
marishachu [46]3 years ago
6 0

Answer: 672 feets

Step-by-step explanation:

Using the solution diagram attached, the vertical height, h of the lighthouse ;

Using trigonometry :

Tanθ = opposite / Adjacent

Tan 2 = h / 804

h = tan 2 * 804

h = 28.076 feets

Using h, we can obtain the distance CB :

Tan θ = opposite / Adjacent

Tan 2 = 28.076 / CB

CB = 28.076 / Tan 12°

CB = 132.08860 feets

Distance between A and B

804 - 132.08860

= 671.9 feets

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Consider the probability that at most 93 out of 127 students will pass their college placement exams. Assume the probability tha
dezoksy [38]

Answer:

Yes, the normal curve can be used as an approximation to the binomial probability.

Step-by-step explanation:

Let <em>X</em> = number of students that pass their college placement exam.

The probability that a given student will pass their college placement exam is, P (X) = <em>p</em> = 0.53.

A random sample of <em>n</em> = 127 students is selected.

The random variable <em>X</em> follows a Binomial distribution.

But the sample size is too large.

A Normal approximation to Binomial can be used to approximate the distribution of proportion <em>p</em>.

The conditions to be satisfied are:

  • <em>np</em> ≥ 10
  • <em>n</em>(1-<em>p</em>) ≥ 10

Check whether the conditions are satisfied as follows:

np=127\times0.53=67.31>10

n(1-p)=127\times(1-0.53)=59.69>10

Both he conditions are satisfied.

Thus, a normal curve can be used as an approximation to the binomial probability.

7 0
3 years ago
On a coordinate plane, 2 lines are shown. Line H J has points (negative 4, negative 2) and (0, 4). Line F G has points (negative
antoniya [11.8K]

Answer:

They are not perpendicular because their slopes are not negative reciprocals.

Step-by-step explanation:

Well first we need to find slope.

\frac{y^2-y^1}{x^2-x^1}

Line HJ)

(-4,-2) , (0,4)

y2 is 4 y1 is -2, so 4 - -2 = 6

0 - -4 = 4

6/4 -> 3/2

Due to the point (0,4) having no x value 4 is the y intercept.

Hence, y = 3/2x + 4 is the slope of line HJ

Line FG)

(-4,1) , (0,-2)

y2 is -2 y1 is 1, so -2 - 1 = -3

0- -4 = 4

Because (0,-2) is missing an x value -2 is the y intercept,

Equation: y = -3/4x - 2

They are not perpendicular because their slopes are not negative reciprocals.

7 0
3 years ago
Read 2 more answers
HURRY: use Pythagorean theorem to solve for the missing variable
olganol [36]
X=10
4 squared + 8 squared
16 + 64
100
square root of 100 is 10
3 0
3 years ago
I don't understand word problems can someone please answer it for me and I need it ASAP.
maksim [4K]

Answer:

Inequality: 3 + 1.2c

What you'd put on graph: 1 ≥ 13.50

5 0
4 years ago
What value of c makes the equation true?
8_murik_8 [283]
Comparing forms, you see that
  4 = ∛c

The value of c is found by cubing both sides of this equation.
  4³ = c = 64
3 0
3 years ago
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