For this problem you are going to need to know the point-slope equation which is:
y-y₁=m(x-x₁)
Now, m=slope and the x and y values are given to us already, so now we just plug our variables into the formula.
It should look like this:
Since all they are asking for is for you to put it into a formula this will be your answer.
Answer:
man thats hard i dont even know
Step-by-step explanation:
Y coordinate on solving both equations comes out to be 0
-2x+3y=-6
3y = -6+2x
put the value of 3y in equation 2nd
5x-2(-6+2x) =15
5x+12-4x = 15
x=3
put value of X in 3y = -6+2x
3y = -6+2*3 = -6+6 = 0
thus y = 0
Answer:
<I= 15degrees
Step-by-step explanation:
Using the cosine rule formulae;
j² = i²+k²-2i cos <J
j² = 37²+57² - 2(37)(57)cos <141
j² = 1369+ 3249- 4218cos <141
j² = 4618- 4218cos <141
j² = 4618-(-3,278)
j²= 7,896
j = √7,896
j = 88.86inches
Next is to get <I
i² = j²+k²-2jk cos <I
37² = 88.86²+57² - 2(88.86)(57)cos <I
1369 = 7,896.0996+ 3249- 10,130.04cos <I
1369 = 11,145.0996 - 10,130.04cos <I
1369 - 11,145.0996 = - 10,130.04cos <I
-9,776.0996=- 10,130.04cos <I
cos <I =9,776.0996 /10,130.04
cos<I = 0.96506
<I = 15.19
<I= 15degrees
3x^2+12x+15=0
Then divide by 3 to get the x by itself.
x^2+4x+5=0
Factor to (x+5) (x-1) and solve for the two values of x.
