The value would have x being equal to 3
Answer:
2√13
Step-by-step explanation:
The distance formula is useful for this. One end of the vector is (0, 0), so the measure of its length is ...
d = √((x2 -x1)² +(y2 -y1)²) = √((6 -0)² +(-4-0)²)
= √(36 +16) = √52 = √(4·13)
d = 2√13 = |(6, -4)|
Answer:
(60.382 ; 83.998)
Step-by-step explanation:
The confidence interval is given as :
Mean ± Margin of error
Mean = 72.19
The margin of error is : Tcritical * s/√n
n = 13 ; s = 15.88
Tcritical at 98%, df = 13-1 = 12 = 2.681
Margin of Error = 2.681 * 15.88/√13 = 11.808
Confidence interval = 72.19 ± 11.808
(60.382 ; 83.998)
Answer:
see below
Step-by-step explanation:
The second equation tells us x = y - 3 so when we plug in y - 3 for x in the first equation we get 4(y - 3) + 3y = -5 → 4y - 12 + 3y = -5 → 7y = 7 → y = 1. Plugging this value into the second equation we get x = y - 3 = 1 - 3 = -2.
