Answer:
The maximum error in the calculated area of rectangle is 5.4 cm².
Step-by-step explanation:
Given : The length and width of a rectangle are measured as 30 cm and 24 cm, respectively, with an error in measured of at most 0.1 cm in each.
To find : Use differentials to estimate the maximum error in the calculated area of rectangle ?
Solution :
The area of the rectangle is 
The derivative of the area is equal to the partial derivative of area w.r.t. length times the change in length plus the partial derivative of area w.r.t. width times the change in width.
i.e. 
Here, 
Substitute the values,
Therefore, the maximum error in the calculated area of rectangle is 5.4 cm².
Answer:
<u>Geometric Progression</u> is the explicit rule for the given sequence: 11, 22, 44, 88...
First term (a) = <u>11</u>
Common ratio (r) = 22/11 = 44/22 = 88/44 = <u>2</u>
Formula used in Geometric Progression is :---
where, 'n' is the required term
Answer:
540
Step-by-step explanation:
There can be so many of such.
Eg. 38 750 38 835
38 795
38 820
Any of the numbers above when rounded to the nearest hundred would result in 38 800.
The idea is such that to make sure the 100 digit is 7 and the 10 digit is 5 or more.
Or if the 100 digit is already 8, then the 10 digit must be less than 5
The triangle is isosceles as two of its sides are equal
⇒ Angles opposite equal sides are equal
⇒ 55°=55°
Now with the help of the Angle-Sum-Property of a Triangle,
⇒ 55°+ 55°+ x= 180°
= x= 180°- 110°
= x= 70°
