Area of figure? Geometry help???

Mathematics

1 answer:

Serga [27]3 years ago

6 0

$A = \dfrac{n}{360^\circ} \times \pi r^2$

$A = \dfrac{172^\circ}{360^\circ} \times 3.14159 \times (4~in.)^2$

$A = \dfrac{172^\circ}{360^\circ} \times 3.14159 \times 16~in.^2$

$A = 24.0~in.^2$

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