Unclear. Did you mean
<span>f(x)= [sqrt of x+3]
--------------------
(x+8)
or did you mean
3
</span><span>f(x)= [sqrt of x] + ----------
x+8
I will focus on the first possibility. The domain of sqrt(x+3) is [-3,infinity).
The domain of x+3
------- is "x is not equal to -8."
x+8
Then the overall domain would be simply [-3, infinity).
</span>
Answer:
34 is it
Step-by-step explanation:
If you would like to evaluate 6 * [5 * (3 - 9) - 1] + 2 / 7 * (8 - 2) + 4, you can calculate this using the following steps:
6 * [5 * (3 - 9) - 1] + 2 / 7 * (8 - 2) + 4 = 6 * [5 * (-6) - 1] + 2/7 * 6 + 4 = 6 * [- 30 - 1] + 12/7 + 4 = 6 * [- 31] + 12/7 + 4 = - 186 + 12/7 + 4 = - 182 + 12/7 = - 1274/7 + 12/7 = - 1262/7
The correct result would be - 1262/7.
Steps:
1. Substitute the y in 4x + 10 with -5x-10
-5x-10= 4x + 10
2. Add 5x on both sides
-10= 9x + 10
3. Subtract 10 on both sides
-20= 9x
4. Divide by 9 on both sides
5. Your answer is
X= -20/9
