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nevsk [136]
3 years ago
14

The flu fighters competed against 40 bands in the soup county battle of the bands. The top 15% will compete in the all virus sta

te finals.how many band will compete in the finals
Mathematics
2 answers:
tankabanditka [31]3 years ago
7 0

Answer:

6

Step-by-step explanation:

If 40 bands competed in the soup county battle of the bands and the top 15% is choose, we can determine the number of bands that will compete in the all virus state finals. We can convert multiply 15% by 40:

=40\cdot{15/100}=4\cdot{15}/10=60/10=6

6 bands will compete in the all virus state finals

DiKsa [7]3 years ago
6 0
6 bands will compete
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Whats 8 times 3 divided by 12
SOVA2 [1]

Answer:

2

Step-by-step explanation:

<u>Step 1:  Convert words into numbers </u>

(8 * 3) / 12

<u>Step 2:  Multiply </u>

(8 * 3) / 12

24 / 12

<u>Step 3:  Divide </u>

24/12

2

Answer:  2

7 0
3 years ago
Read 2 more answers
Find MZP. The diagram is not to scale.
Ad libitum [116K]

Answer:

p= 50

Step-by-step explanation:

the angle that measures 130 is supplementary to the angle below, meaning the other angle must equal 50 degrees. This angle is an alternate interior angle with angle p, making them congruent.

3 0
3 years ago
Which expression is equivalent to √48x5, if x&gt; 0?
Lerok [7]

Answer:

C. 4x²√(3x)

Step-by-step explanation:

if x > 0

\sqrt{48x^{5}} =\sqrt{48} \times \sqrt{x^{5}}

          =\sqrt{16\times 3} \times \sqrt{x^{4}\times x}

          =\sqrt{16} \times \sqrt{3} \times \sqrt{x^{4}} \times \sqrt{x}

          =4\times \sqrt{3} \times \sqrt{\left( x^{2}\right)^{2}  } \times \sqrt{x}

          =4\times \sqrt{3} \times x^{2}\times \sqrt{x}

          =4\times x^{2} \times  \sqrt{3} \times \sqrt{x}

          =4\times x^{2}\times \sqrt{3x}

8 0
2 years ago
Find two consecutive even integers such that the smaller added to three times the larger gives a sum of 54
REY [17]
Let n be the first even integer, and n+2 will be the second even integer. (Why? Think 2 and 4, 2+2=4. This is the case for every consecutive even integers).

n + 3(n+2) = 54
n + 3n + 6 = 54
4n = 48
n = 12, n+2 = 14
7 0
3 years ago
Read 2 more answers
A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe
adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

\frac{dC}{dt}=Ci*Qi-Co*Qo

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

\frac{dC}{dt}=-Co*Qo

Rearranging the equation, it becomes

\frac{dC}{C}=-Qo*dt

Integrating both sides

\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\

The final equation for the concentration of salt at any given time is

C=exp^{-3*t-0.693}

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}=  -\frac{-0.266}{3}=0.088

5 0
3 years ago
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