Answers: G) ∠BCS = 57.5°
H) ∠FHI = 72°
I) ∠ACB and also ∠DCH
J) ∠CHD (which can also be named ∠BHE)
<u>Step-by-step explanation:</u>
First of all, I checked your answers for A-F and they are all correct. YAY!
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G) Draw a point halfway between B and D and label it S. Then draw a ray from C passing through S.
∠ACB and ∠BCD are supplementary so
65° + ∠BCD = 180°
⇒ ∠BCD = 115°
Since ray CS bisects ∠BCD, then ∠BCS is half of ∠BCD.

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H) The instructions state to draw a line from H to F. This divides ∠DHI into two angles: ∠FHD and ∠FHI. Since lines BI and EG are perpendicular, then ∠DHI = 90°. It is given that ∠FHI is 4 times larger than ∠FHD so we can use substitution...
∠FHD + ∠FHI = ∠DHI
∠FHD + 4(∠FHD) = 90°
5(∠FHD) = 90°
∠FHD = 18°
∠FHI = 4(∠FHD)
= 4 (18°)
= 
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I) adjacent means they share a side and supplementary means they form a straight angle. There are two angles that are adjacent and supplementary to ∠ACH.
- ACB - they share side AC and are supplementary on BH
- DCH - they share side CH and are supplementary on AD
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J) congruent means equal and adjacent means they share a side.
The angle that is not congruent nor adjacent to ∠GHI is its vertical angle, which is ∠CHD. <em>Notice that ∠CHD is the same as ∠BHE.</em>
Answer:
equation: 2.75 g/cm^3 * 1 m *3 m* (100 cm/1 m)^2 *4 cm * (1 kg/1000 g)
Step-by-step explanation:
countertop mass, m =?
density, ρ = 2.75 g/cm^3
wide, w = 1 m
long, l = 3 m
thick, t = 4 cm
countertop volume, V = w*l*t = 1 m *3 m*4 cm* (100 cm/1 m)^2
Isolating mass from density definition gives
ρ = m/V
m = ρ*V
m = 2.75 g/cm^3 * 1 m *3 m* (100 cm/1 m)^2 *4 cm * (1 kg/1000 g)
Answer:
2. <
Step-by-step explanation:
A units digit of 0 is less than a units digit of 1, so ...
0.9 < 1.1
Answer:
I think your answer is, A, C, D, F
Simplify,,,,,,,,,,,,,,,,,,,
tatuchka [14]
It is D , if you plus into a calculator it simplifies for you !!