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const2013 [10]
3 years ago
14

PLEASE HELP Solve for x in the equation 2x^2 - 5x + 1 = 3

Mathematics
2 answers:
Alchen [17]3 years ago
3 0
Answer:

<span>x=<span><span>5±<span>√41</span></span>4</span></span>

Explanation:

<span>2<span>x2</span>−5x+1=3</span>

<span><span>aaaaaaa</span>−3a−3<span>aaa</span></span>Subtract 3 from both sides

<span>2<span>x2</span>−5x−2=0</span>

This equation is not factorable, so use the quadratic formula.

<span>x=<span><span>−b±<span>√<span><span>b2</span>−4ac</span></span></span><span>2a</span></span><span>aaa</span></span> for<span><span>aaa</span>a<span>x2</span>+bx+c=0</span>

<span>a=2,b=−5,c=−2</span>

<span>x=<span><span>−<span>(−5)</span>±<span>√<span><span><span>(−5)</span>2</span>−4<span>(2)</span><span>(−2)</span></span></span></span><span>2⋅2</span></span></span>

<span>x=<span><span><span>5±<span>√41</span></span>4</span></span></span>

hope this helped :)

alisa202

algol133 years ago
3 0

Answer:

x=\frac{5\pm\sqrt{41}}{4}

Step-by-step explanation:

We have been given an equation 2x^2-5x+1=3. We are asked to solve for x.

First of all, we will convert our given equation in standard form of equation as:

2x^2-5x+1-3=3-3

2x^2-5x-2=0

Now, we will use quadratic formula to solve for x.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-2)}}{2(2)}

x=\frac{5\pm\sqrt{25+16}}{4}

x=\frac{5\pm\sqrt{41}}{4}

Therefore, the solutions for our given equation are x=\frac{5\pm\sqrt{41}}{4}.

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