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const2013 [10]
2 years ago
14

PLEASE HELP Solve for x in the equation 2x^2 - 5x + 1 = 3

Mathematics
2 answers:
Alchen [17]2 years ago
3 0
Answer:

<span>x=<span><span>5±<span>√41</span></span>4</span></span>

Explanation:

<span>2<span>x2</span>−5x+1=3</span>

<span><span>aaaaaaa</span>−3a−3<span>aaa</span></span>Subtract 3 from both sides

<span>2<span>x2</span>−5x−2=0</span>

This equation is not factorable, so use the quadratic formula.

<span>x=<span><span>−b±<span>√<span><span>b2</span>−4ac</span></span></span><span>2a</span></span><span>aaa</span></span> for<span><span>aaa</span>a<span>x2</span>+bx+c=0</span>

<span>a=2,b=−5,c=−2</span>

<span>x=<span><span>−<span>(−5)</span>±<span>√<span><span><span>(−5)</span>2</span>−4<span>(2)</span><span>(−2)</span></span></span></span><span>2⋅2</span></span></span>

<span>x=<span><span><span>5±<span>√41</span></span>4</span></span></span>

hope this helped :)

alisa202

algol132 years ago
3 0

Answer:

x=\frac{5\pm\sqrt{41}}{4}

Step-by-step explanation:

We have been given an equation 2x^2-5x+1=3. We are asked to solve for x.

First of all, we will convert our given equation in standard form of equation as:

2x^2-5x+1-3=3-3

2x^2-5x-2=0

Now, we will use quadratic formula to solve for x.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-2)}}{2(2)}

x=\frac{5\pm\sqrt{25+16}}{4}

x=\frac{5\pm\sqrt{41}}{4}

Therefore, the solutions for our given equation are x=\frac{5\pm\sqrt{41}}{4}.

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Answer:

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Step-by-step explanation:

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Now, focus your eyes on the circle. We are shown that the diameter of this circle is 42 mm, but we only want the radius. Since the radius is half the diameter, the radius is 21 mm. Now, we can solve for the area of the circle.

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