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const2013 [10]
3 years ago
14

PLEASE HELP Solve for x in the equation 2x^2 - 5x + 1 = 3

Mathematics
2 answers:
Alchen [17]3 years ago
3 0
Answer:

<span>x=<span><span>5±<span>√41</span></span>4</span></span>

Explanation:

<span>2<span>x2</span>−5x+1=3</span>

<span><span>aaaaaaa</span>−3a−3<span>aaa</span></span>Subtract 3 from both sides

<span>2<span>x2</span>−5x−2=0</span>

This equation is not factorable, so use the quadratic formula.

<span>x=<span><span>−b±<span>√<span><span>b2</span>−4ac</span></span></span><span>2a</span></span><span>aaa</span></span> for<span><span>aaa</span>a<span>x2</span>+bx+c=0</span>

<span>a=2,b=−5,c=−2</span>

<span>x=<span><span>−<span>(−5)</span>±<span>√<span><span><span>(−5)</span>2</span>−4<span>(2)</span><span>(−2)</span></span></span></span><span>2⋅2</span></span></span>

<span>x=<span><span><span>5±<span>√41</span></span>4</span></span></span>

hope this helped :)

alisa202

algol133 years ago
3 0

Answer:

x=\frac{5\pm\sqrt{41}}{4}

Step-by-step explanation:

We have been given an equation 2x^2-5x+1=3. We are asked to solve for x.

First of all, we will convert our given equation in standard form of equation as:

2x^2-5x+1-3=3-3

2x^2-5x-2=0

Now, we will use quadratic formula to solve for x.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-2)}}{2(2)}

x=\frac{5\pm\sqrt{25+16}}{4}

x=\frac{5\pm\sqrt{41}}{4}

Therefore, the solutions for our given equation are x=\frac{5\pm\sqrt{41}}{4}.

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Please help ! only G-J 15 points for this.
kogti [31]

Answers: G) ∠BCS = 57.5°

                H) ∠FHI = 72°

                 I) ∠ACB and also ∠DCH

                 J) ∠CHD (which can also be named ∠BHE)

<u>Step-by-step explanation:</u>

First of all, I checked your answers for A-F and they are all correct. YAY!

********************************************************************************************

G) Draw a point halfway between B and D and label it S. Then draw a ray from C passing through S.

∠ACB and ∠BCD are supplementary so

  65°    +    ∠BCD  =     180°

⇒               ∠BCD  =     115°

Since ray CS bisects ∠BCD, then ∠BCS is half of ∠BCD.

\angle BCS=\dfrac{1}{2} (\angle BCD)\\\\. \quad \quad=\dfrac{1}{2}(115^o)\\\\. \quad \quad =\large\boxed{57.5^o}

********************************************************************************************

H) The instructions state to draw a line from H to F.  This divides ∠DHI into two angles: ∠FHD and ∠FHI.  Since lines BI and EG are perpendicular, then ∠DHI = 90°.  It is given that ∠FHI is 4 times larger than ∠FHD so we can use substitution...

∠FHD + ∠FHI = ∠DHI

∠FHD + 4(∠FHD) = 90°

             5(∠FHD) = 90°

                ∠FHD  = 18°

∠FHI = 4(∠FHD)

        = 4 (18°)

        = \large\boxed{72^o}

********************************************************************************************

I) adjacent means they share a side and supplementary means they form a straight angle. There are two angles that are adjacent and supplementary to ∠ACH.  

  • ACB - they share side AC and are supplementary on BH
  • DCH - they share side CH and are supplementary on AD

********************************************************************************************

J) congruent means equal and adjacent means they share a side.

The angle that is not congruent nor adjacent to ∠GHI is its vertical angle, which is ∠CHD.  <em>Notice that ∠CHD is the same as ∠BHE.</em>

5 0
3 years ago
The density of granite is about 2.75 grams per cubic centimeter. Suppose you have a granite countertop for a kitchen that is 1 m
Ugo [173]

Answer:

equation: 2.75 g/cm^3 * 1 m *3 m* (100 cm/1 m)^2 *4 cm * (1 kg/1000 g)

Step-by-step explanation:

countertop mass, m =?

density, ρ = 2.75 g/cm^3

wide, w = 1 m

long,  l = 3 m

thick, t = 4 cm

countertop volume, V = w*l*t = 1 m *3 m*4 cm* (100 cm/1 m)^2

Isolating mass from density definition gives

ρ = m/V

m = ρ*V

m = 2.75 g/cm^3 * 1 m *3 m* (100 cm/1 m)^2 *4 cm * (1 kg/1000 g)

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Answer:

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