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Bingel [31]
3 years ago
11

two models are shown. Each model has been shaded grey to represent a fraction. wgucj statement is true about the fractions 3/4 a

nd 6/8​

Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

The third, they are equivalent because the size of the shaded area is the same.

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how to solve 2 to the 8th power divided by 2 to the 9 power? Im trying to find the right exponets topic for this but not having
MArishka [77]

2 to the negative 1 power. When you divide two exponents with the same base, you subtract the two exponents to get your answer.



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7 0
3 years ago
Draw a picture in the space in the right to show how you would find 1/2 of 8 marbles
777dan777 [17]
Simply present that you would split them up as a factor of two. ( make two lines going either vertically or horizontally. place in varriations, a marble in one line and a marble in the other and then count the leftover
7 0
4 years ago
HELPPPPPPPP!!!!!!!!!!
Novosadov [1.4K]

Step-by-step explanation:

98 = 188t - 16t^2

-16t^2 + 188t = 98

-16t^2 + 188t - 98 = 0

8t^2 - 94t + 49 = 0

Use the quadratic formula with a = 8 , b = -94 , c = 49 to get the solutions

t = [(47 - root 1817) / 8]≈ 0.55

and

t = [(47 + root 1817) / 8] ≈ 11.20

8 0
3 years ago
1. What does it mean that Nikoleta is in the 10th percentile for length and weight? Is that a desirable statistic if she was in
VladimirAG [237]

Explanation:

1. It means that Nikoleta is longer and heavier than 10% of children her age.

2. We generally expect that a change from being in the 50th percentile to the 10th percentile signifies a condition that is interfering with normal growth. That is not usually considered desirable.

5 0
4 years ago
Read 2 more answers
A ball is thrown upward with an initial velocity of 96 ft/sec from a height 640 ft. Its height​ h, in​ feet, after t seconds is
olchik [2.2K]
Check the picture below.

thus is at 0 = -16t² + 96t +640,

\bf 0=-16t^2+96t+640\implies 0=-16(t^2-6t-40)
\\\\\\
0=t^2-6t-40\implies 0=(t-10)(t+4)\implies t=
\begin{cases}
\boxed{10}\\
-4
\end{cases}

well, clearly it can't be a negative value for the elapsed seconds, so it can't be -4.

5 0
4 years ago
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