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3 years ago

11

two models are shown. Each model has been shaded grey to represent a fraction. wgucj statement is true about the fractions 3/4 a

nd 6/8

1 answer:

jeka57 [31]3 years ago

8 0

Answer:

The third, they are equivalent because the size of the shaded area is the same.

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Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

Leni [432]

Answer: $\dfrac{2x^2-1}{x(x^2-1)}$

Step-by-step explanation:

The given function : $y=\ln(x(x^2 - 1)^{\frac{1}{2}})$

$\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}$ [ $\because \ln(ab)=\ln a +\ln b$ ]

$\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}$ [ $\because \ln(a)^n=n\ln a$ ]

Now , Differentiate both sides with respect to x , we will get

$\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1)$ (By Chain rule)

[Note : $\dfrac{d}{dx}(\ln x)=\dfrac{1}{x}$ ]

$\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)$

[ $\because \dfrac{d}{dx}(x^n)=nx^{n-1}$ ]

$=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}$

Hence, the derivative of the given function is $\dfrac{2x^2-1}{x(x^2-1)}$ .

8 0

4 years ago

Scott works on cars. He charges $35 for each car plus $7 per hour. The total bill was $63. The equation that matches this is 35x

GuDViN [60]

He worked on the car for 4 hours. 35+7+7+7+7=63.

3 0

3 years ago

Use pi=3<br> Calculate the area of a circle with a diameter of 10cm

GalinKa [24]

Area of a circle is 75 cm².

Area of a circle is computed by multiplying pi to the square of the radius.

A = πr²

diameter = 10 cm
radius = d/2 = 10/2 = 5 cm
pi = 3

A = 3(5cm²)
A = 3(25cm²)
A = 75 cm²

7 0

3 years ago

Which is equivalent to 2564 3/4^<br> Help

Yuliya22 [10]

The answer is 64, happy to help!

:)

4 0

3 years ago

ANSWER FAST PLS HAVE 5 MIN FOR THIS

Kobotan [32]

Answer:

Y=375x

Step-by-step explanation:

thats the answer

6 0

3 years ago