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3 years ago

Which number is multiple of 13? A) 27 B) 44 C) 51 D) 65

Mathematics

2 answers:

In-s [12.5K]3 years ago

8 0

Answer:

D, 65 is a multiple of 13

Step-by-step explanation:

13 ,26 ,39, 52, 65, 78 ,91, 104 ,117, 130 ,143, 156, 169, 182 ,195 ,208 ,221, 234, 247, 260 ,273 ,286 ,299 ,312, 325, 338, 351, 364, 377, 390, 403, 416, 429, 442, 455 ,468, 481 494, 507, 520, 533, 546, 559, 572, 585, 598, 611, 624, 637,

MissTica3 years ago

4 0

your answer is simple. all you do is add 13 over and over again until you get one of those answers. or in this case the answer is D

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12 5/6 - 7 3/10 = Jan rig cufogy8vohc68

noname [10]

Exact Answer: 83/15

Decimal Answer: 5.53 (bar notation above 3)

Mixed Number Answer: 5 8/15

Step-by-step explanation:

Convert the mixed numbers to improper fractions, then find the LCD and combine.

8 0

3 years ago

Credit sales are collected as follows:65 percent in the month of the sale.25 percent in the month after the sale.10 percent in t

Vitek1552 [10]

Answer:

Step-by-step explanation:

a) November sales = (Total Uncollected Sales - Uncollected Sales from December) / Collection rate after two months

= ($121,100 - $87,300) / 0.20

November sales = $169, 000.00

b) December sales = Uncollected sales from December / Collection rate of the previous month sales,

Therefore: December sales = $87,300 / 0.45 = $194,000

December sales = $194,000.00

c) Each month's collection for the company are:

Collections for ech month = 0.20(Sales from 2 months ago) + 0.25(Last month's sales) + 0.55 (Current sales)

January collections = 0.20($169000.00) + 0.25($194,000.00) + 0.55($132,000)

January collections = $154,900.00

February collections = 0.20($194,000.00) + 0.25($132,000) + 0.55($149,000)

February collections = $153,750.00

March collections = 0.20($132,000) + 0.25($149,000) + 0.55($164,000)

March collections = $153,850.00

4 0

4 years ago

The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the

Paul [167]

So.. hmm notice the picture here

we know the length is 59 more than twice the width,
twice the width, 2 * w, or 2w
59 more than that
2w + 59

we also know that, whatever that is, the diagonal of it is,
2 more inches than that, or
(2w + 59) + 2

now.. use the pythagorean theorem
$\bf c^2=a^2+b^2\implies \qquad 
\begin{cases}
a=2w+59\\
b=w\\
c=(2w+59)+2\to 2w+61
\end{cases}
\\\\\\
(2w+61)^2=(2w+59)^2+(w)^2
\\ \qquad\qquad \uparrow\qquad \qquad\qquad \qquad \uparrow \\
\textit{expand using binomial theorem, or FOIL}$

you'd end up with a quadratic, after simplifying, solve for "w"

7 0

3 years ago

Which Number produces a rational number when added to 0.25

joja [24]

The answer is b. 777777777777( dont mind the 7's)

5 0

3 years ago

Stephanie's school is selling tickets to a play. On the first day of ticket sales the school sold 4 adult tickets and 10 student

klemol [59]

Answer:

The price of

1 adult ticket = $15

1 student ticket = $9

Step-by-step explanation:

Let

The price of adult tickets be represented by a

The price of student tickets be represented by s

Therefore:

On the first day of ticket sales the school sold 4 adult tickets and 10 student tickets for a total of $150.

4a + 10s = $150.... Equation 1

The school took in $105 on the second day by selling 1 adult ticket and 10 student tickets.

a + 10s = $105.... Equation 2

a = $105 - 10s

Therefore, we substitute : $105 - 10s = a in Equation 1

4a + 10s = $150.... Equation 1

4($105 - 10s) + 10s = $150

$420 - 40s + 10s = $150

Collect like terms

- 40s + 10s = $150 - $420

-30s = -$270

Divide both sides by -30

-30s/-30 = -$270/-30

s = $9

We find a

a = $105 - 10s

a = $105 - 10($9)

a = $105 - $90

a = $15

Therefore, the price of

1 adult ticket = $15

1 student ticket = $9

7 0

3 years ago