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4 years ago

Compare 1/2 with 3/4 using ( <,>,=).

1 answer:

6 0

Howdy there! =) The answer to your question is < because we should make them have common denominator so 1*2=2 and 2*2=4 so 2/4. 3 is bigger than 2 so it is less than. Also because 75% is bigger than 50%

Hope I helped! :D

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Bryan is making a wooden cube to hold his little sisters jewelry.The volume of the cube is 512 in.3. What is the length of one s

Jlenok [28]

Answer:

The length of one side of the jewelry box is 8 inches

Step-by-step explanation:

we know that

The volume of a cube is equal to

$V=b^{3}$

where

b is the length side of the cube

In this problem we have

$V=512\ in^3$

substitute in the equation and solve for b

$512=b^{3}$

$b=\sqrt[3]{512}$

$b=8\ in$

8 0

3 years ago

Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul

ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that $p = 0.5$

12 young adults were randomly selected

This means that $n = 12$

(a) What is the probability that more than 7 preferred McDonald's?

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000$

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194$

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226$

$P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193$

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787$

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since $p = 1-p = 0.5$ , this is the same as b) above.

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0

3 years ago

what is the area of the figure 26.8square meters 38.8square meters 43.2square meters 50.8square meters

Sveta_85 [38]

Answer:

Choise B..... 38.8

Step-by-step explanation:

trust

3 0

3 years ago

What is the solution to the equation? 13 3/4 +x= 7 1/4

Butoxors [25]

Answer:

x = $6\frac{1}{2}$

Step-by-step explanation:

$13\frac{3}{4}+x=7\frac{1}{4}$

(subtract $13\frac{3}{4}$ from both sides)

$x=6\frac{2}{4}$ or $6\frac{1}{2}$

4 0

4 years ago

in the function y+2=1/3(x-4)^2, what effect does the number4 have on the graph, as compared to the graph of y=x^2

Afina-wow [57]

Answer: It shifts the graph four units to the right.

Step-by-step explanation: I just did it on apex. Your welcome guys stay safe and dream big:)

7 0

3 years ago