Help me please,Thanks;)

Someone pls help me with this

frosja888 [35]

Answer:

4.25 wewewewewewewewewewewewewewewewewewewewewewewewewewewewewewewewewewewewewewewe

Step-by-step explanation:

3 0

2 years ago

Given the following formula, solve for v. s = 1/2a^2v + c

weeeeeb [17]

Since there is no initial condition, the exact value of v cannot be determined, but you can set the equation up for a general evaluation of the situation.

s = 1/2a^2*v+c

First you need to subtract c from both sides to get

s-c = 1/2a^2*v

then you can just divide both sides by 1/2a^2 to get v

(2(s-c))/a^2=v

when dividing a fraction, such as 1/2, make sure to keep in mind that you're really multiplying the flipped version, so that dividing by 1/2 means multiplying by 2.

7 0

3 years ago

Read 2 more answers

Pratap puri rowed 10 miles down a river in 2 hours, but the return trip took him 2 and one half hours. Find the rate pratap can

N76 [4]

Answer:

Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.

Step-by-step explanation:

Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.

We know that, $Speed = \frac{Distance}{Time}$

So, the speed of Pratap with the current will be: $(\frac{10}{2})miles/hour = 5$ miles/hour

and the speed of Pratap against the current will be: $(\frac{10}{2.5})miles/hour = 4$ miles/hour.

Suppose, the rate of Pratap in still water is $x$ and the rate of current is $y$ .

So, the equations will be........

$x+y= 5 .............................. (1)\\ \\ x-y=4 .............................. (2)$

Adding equation (1) and (2) , we will get......

$2x=9\\ \\ x=\frac{9}{2}= 4.5$

Now, plugging this $x=4.5$ into equation (1), we will get.....

$4.5+y=5\\ \\ y=5-4.5 =0.5$

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.

6 0

3 years ago

Raffle tickets were sold for a school fundraiser to parents, teachers, and students. 563 tickets were sold to teachers. 888 more

Llana [10]

Given :

Raffle tickets were sold for a school fundraiser to parents, teachers, and students. 563 tickets were sold to teachers. 888 more tickets were sold to students than to teachers. 904 tickets were sold to parents.

To Find :

How many tickets were sold to students.

Solution :

Ticket sold to teachers, T = 563 .

Ticket sold to parents, P = 904 .

Let, ticket sold to students are S.

Now, it is given that :

S = T + 904

S = 563 + 904

S = 1467 students

Therefore, tickets sold to students are 1467 .

Hence, this is the required solution.

6 0

2 years ago

Suppose that a car rental agency charges a fixed amount per day plus an amount per mile for renting a car. Heidi rented a car on

elena55 [62]

9514 1404 393

Answer:

f(x) = 0.15x +25

Step-by-step explanation:

We are given two points:

(x, y) = (180, 52) or (350, 77.50)

The slope is given by ...

m = (y2 -y1)/(x2 -x1)

m = (77.50 -52)/(350 -180) = 25.50/170 = 0.15

The y-intercept is given by ...

b = y -mx

b = 52 -0.15×180 = 25

Then the equation for the linear function is ...

f(x) = mx +b

f(x) = 0.15x +25

8 0

2 years ago