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3 years ago

5

What's a non iscoceles trapezoid

1 answer:

nadezda [96]3 years ago

6 0

It'd be a trapezoid that either has 4 different unique line lengths, or 3 or more sides are the same length.

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Please help will give brainliest answer

IgorC [24]

Answer:

42.5 units^2

Step-by-step explanation:

We can split up this shape into smaller ones.

First we can start with the large rectangle on top

We know its 9 by 3.5

9x3.5=31.5

The large rectangle is 31.5, at the end we'll add them all together

Next we can work on the small triangle on the bottom left

Area= bh/2

Both the base and height are 2, 2x2=4 4/2=2, The area of that triangle is 2

Now we can work on the triangle on the bottom right. This time the base is 5

5x2=10 10/2=5, The area of that triangle is 5

Now we need to figure out the square/rectangle at the bottom. We only know one side is 2. We can figure out the top side. Since the very top of the shape is 9, we know that the bottom side of the large rectangle also has to add to 9. We know the values 2 and 5. 2+5+x=9, the missing length that's there is 2.

Now we know the small square is 2 by 2. 2x2=4 The square's area is 4

Now we add them all up.

31.5+2+5+4=42.5

8 0

3 years ago

Please help!! MathsWatch, Surd Expressions, Clip 207c

dexar [7]

Answer:

$A=(72+36\sqrt{3})\ mm^2$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

$b=AB+BC+CD+DE$ ----> by segment addition postulate

substitute

$b=3+3+3+3=12\ mm$

step 2

Find the height of rectangle

$a=FB+CG+GH$ ---> by segment addition postulate

substitute the given values

$a=3+CG+3\\a=6+CG$

Find the length sides CG

Applying the Pythagorean Theorem

$BG^2=BC^2+CG^2$

substitute the given values

$6^2=3^2+CG^2$

$CG^2=6^2-3^2$

$CG=\sqrt{27}\ mm$

simplify

$CG=3\sqrt{3}\ mm$

therefore

$a=(6+3\sqrt{3})\ mm$

step 3

Find the area of rectangle

$A=ab$

we have

$a=(6+3\sqrt{3})\ mm$

$b=12\ mm$

substitute

$A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2$

8 0

3 years ago

The index number representing the price level changes from 109 to 113 in one year. The inflation rate during the year is _____ p

Dima020 [189]

First, get the difference between the price level changes.

$113-109=4$

Then, divide it by the initial price level, which is 109.

$\frac{4}{109}=0.0367$

Multiply by 100 to get its percent.

$0.0367\times100=3.67$

Thefore, the inflation rate during the year is 3.67 percent.

8 0

11 months ago

What is the equation of the following line? be sure to scroll down first to see all answer options

andreyandreev [35.5K]

Answer:

The equation for the following graph:

$y = -\frac{1}{5}x$

Step-by-step explanation:

- You first need to find the slope by using the <u>slope formula</u>:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

(where $(x_{1},y_{1})$ is the first point and $(x_{2}, y_{2})$ is the second point)

-Use the given points $(0,0)$ and $(10, -2)$ from the graph for the formula:

$m = \frac{-2 - 0}{10 - 0}$

Then, you solve:

$m = \frac{-2 - 0}{10 - 0}$

$m = -\frac{1}{5}$

After you have found the slope, use the slope $-\frac{1}{5}$ and the first point $(0,0)$ for the <u>point-slope formula:</u>

$y - y_{1} = m ( x - x_{1})$

<u>(</u>where $m$ is the slope and $(x_{1}, y_{1})$ is the first point)

$y - 0 = -\frac{1}{5} ( x - 0)$

Then, you solve:

$y - 0 = -\frac{1}{5} ( x - 0)$

$y - 0 = -\frac{1}{5}x - 0$

$y - 0 + 0 = -\frac{1}{5} - 0 + 0$

$y = -\frac{1}{5}x$

So, the equation for the following graph is $y = -\frac{1}{5}x$ .

7 0

2 years ago

Andy drove 840 miles in 12 hours. How far could he drive in 3 hours

WITCHER [35]

210 miles in 3 hours

7 0

3 years ago

Read 2 more answers