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poizon [28]
3 years ago
8

Assume that x is a char variable that has been declared and already given a value . write an expression whose value is true if a

nd only if x is a upper-case letter.
Computers and Technology
1 answer:
olga nikolaevna [1]3 years ago
3 0
#include <ctype.h>

int result;

result = ( toupper( x ) == x ) ? 1 : 0;
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"giga" can mean both 109 and 230. explain to what each refers. can this cause confusion when reading a computer advertisement?
inn [45]
Giga usually means 10^9

We're trying to work giba, which is 2^30 into the vocabulary to differentiate them because of the confusion and difference that they create.
7 0
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What do you call the specific format that is used to give credit to someone else’s work, words or ideas?
Deffense [45]
It would be called a citation.
6 0
3 years ago
Read 2 more answers
You are given an unsorted array x of elements that implement the Comparable interface. There are no duplicates in this array. Yo
Andrei [34K]

Answer:

boolean isEven = false;

if (x.length % 2 == 0)

isEven = true;

Comparable currentMax;

int currentMaxIndex;

for (int i = x.length - 1; i >= 1; i--)

{

currentMax = x[i];

currentMaxIndex = i;

for (int j = i - 1; j >= 0; j--)

{

if (((Comparable)currentMax).compareTo(x[j]) < 0)

{

currentMax = x[j];

currentMaxIndex = j;

}

}

x[currentMaxIndex] = x[i];

x[i] = currentMax;

}

Comparable a = null;

Comparable b = null;

if (isEven == true)

{

a = x[x.length/2];

b = x[(x.length/2) - 1];

if ((a).compareTo(b) > 0)

m = a;

else

m = b;

}

else

m = x[x.length/2];

8 0
4 years ago
When an array is passed to a function, it is actually ________ the array that is/are passed?
MAVERICK [17]
Hello <span>MrSnuffleBuns4243 
</span>

Answer: When an array is passed to a function, it is actually  <span>the starting memory address of </span>the array that is/are passed?

Hope this helps
-Chris
5 0
4 years ago
import java.util.Scanner; public class StudentScores { public static void main (String [] args) { Scanner scnr = new Scanner(Sys
Delvig [45]

Answer:

The code at 'Your solution goes here' is in the bold font given

Explanation:

import java.util.Scanner;

public class StudentScores {

   public static void main(String[] args) {

       Scanner scnr = new Scanner(System.in);

       final int SCORES_SIZE = 4;

       int[] oldScores = new int[SCORES_SIZE];

       int[] newScores = new int[SCORES_SIZE];

       int i;

       for (i = 0; i < oldScores.length; ++i) {

           oldScores[i] = scnr.nextInt();

       }

       for (i = 0; i < oldScores.length - 1; ++i) {

           newScores[i] = oldScores[i+1];

       }

       newScores[oldScores.length-1] = oldScores[0];

       for (i = 0; i < newScores.length; ++i) {

           System.out.print(newScores[i] + " ");

       }

       System.out.println();

   }

}

4 0
3 years ago
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